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musickatia [10]
4 years ago
6

Mhm sorry but I need help on this

Mathematics
2 answers:
Georgia [21]4 years ago
7 0

Answer:

x>2

Step-by-step explanation:

balu736 [363]4 years ago
4 0

Answer:   x \ge 2

The x part is already taken care of, so you'll fill the rest into the box.

On a keyboard you could type x >= 2 to mean x \ge 2

=====================================================

Explanation:

We have a closed or filled in circle at x = 2. This means 2 is included in the shaded region solution set. So we'll have "or equal to" as part of the inequality.

We'll also have "greater than" because how the shading is to the right of the closed circle.

So put together that's why the graph represents x \ge 2

Something like x = 5 is a solution because 5 \ge 2 is true

Something like x = 0 is not a solution because 0 \ge 2 is false

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Last week, an office group spent $122 on 6 cheese pizzas and 4 salads. This week, the group spent $192 on 8 cheese pizzas and 6
kondaur [170]

Answer:

The system of equations is

6c+4s=122

8c+6s=192

Step-by-step explanation:

Let

c----->  the number of cheese pizzas

s----> the number of salads

we know that

6c+4s=122 -----> equation A

8c+6s=192 -----> equation B  

8 0
3 years ago
Read 2 more answers
Which expression has both eight and N as factors
elena-s [515]
I don’t see no expressions
7 0
3 years ago
What is the antiderivative of sin^2(x)cos^2(x)?
marin [14]

Answer:

\frac{x}{8}-\frac{\sin(4x)}{32}+C

Step-by-step explanation:

[Most of the work here comes from manipulating the trig to make the term (integrand) integrable.]

Recall that we can express the squared trig functions in terms of cos(2x). That is,

\cos(2x)=2\cos^2x-1 \\ \cos(2x)=1 - 2\sin^2x.

And so inverting these,

\cos^2x=\frac{1}{2} (1+\cos2x) \\ \sin^2x=\frac{1}{2} (1-\cos2x).

Multiply them together to obtain an equivalent expression for sin^2(x)cos^2(x) in terms of cos(2x).

\sin^2x \cdot \cos^2x =\frac{1}{2} (1-\cos2x) \cdot \frac{1}{2} (1+\cos2x) = \frac{1}{4}(1-\cos^2(2x)).

Notice we have cos^2(2x) in the integrand now. We've made it worse! Let's try plugging back in to the first identity for cos^2(2x).

\cos(2x)=2\cos^2x-1 \Rightarrow \cos(4x)=2\cos^2(2x)-1 \Rightarrow \cos^2(2x) = \frac{1}{2}(1+\cos(4x))

So then,

\sin^2x \cdot \cos^2x = \frac{1}{4}(1-\cos^2(2x)) = \frac{1}{4}(1-\frac{1}{2}(1+\cos(4x))) = \frac{1}{4}(1-\frac{1}{2}-\frac{1}{2}\cos(4x))=\frac{1}{8}(1-\cos(4x)).

This is now integrable (phew),

\int \sin^2x\cos^2x \ dx = \int \frac{1}{8}(1-\cos(4x)) \ dx = \frac{1}{8} \int (1-\cos(4x)) \ dx = \frac{1}{8}(x-\frac{1}{4}\sin(4x))+C.

7 0
3 years ago
WILL GIVE BRAINLIEST, ANSWER FAST PLEASE
Marizza181 [45]

Answer:

2( \frac{2}{5} x + 2) =  \frac{4}{5} x + 4

Step-by-step explanation:

Use the distributive property.

6 0
2 years ago
A line passes through the point (0, 3) and has a slope of 5/4 What is the equation of the line?
Misha Larkins [42]
D.5x+4y=3 is the answer
6 0
3 years ago
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