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3 years ago

What is the x-intersept

Mathematics

1 answer:

sladkih [1.3K]3 years ago

4 0

Answer:

-2

Step-by-step explanation:

-2 because that is where the line intersects on the x-axis

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Pls helppppp 25 pt and brainiest for whoever answers it right.

defon

<h3><u>Given</u><u>:</u><u>-</u></h3>

Perimeter of parallelogram = 66 ft

One side,a = 3x + 1

Other side,b = 2x - 3

Find the longest side of a parallelogram.

<h3><u>Formula</u><u> </u><u>used</u><u>:</u><u>-</u></h3>

Perimeter of parallelogram = 2 ( a + b )

<h3><u>Solution:-</u><u> </u></h3>

We know that,

Perimeter of parallelogram = 2 ( a + b )

★ Substituting the values in the above formula,we get:

⇒ 66 = 2 ( 3x + 1 + 2x - 3 )

⇒ 66 = 2 ( 5x - 2 )

⇒ 66/2 = 5x - 2

⇒ 33 = 5x - 2

⇒ 5x - 2 = 33

⇒ 5x = 33 + 2

⇒ 5x = 35

⇒ x = 35/5

⇒ x = 7 ft

Now,

One side,a = 3x + 1

★ Putting the value of x

⇒ 3 × 7 + 1

⇒ 21 + 1

⇒ 22 ft

Other side,b = 2x - 3

★ Putting the value of x

⇒ 2 × 7 - 3

⇒ 14 - 3

⇒ 11 ft

Hence,the longest Side of given parallelogram is 22 ft ( 3x + 1 ) .

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4 years ago

The can is 12 cm high and the diameter is 8 cm.

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3 years ago

What Is the property of (6 +56) + 5 = (56 + 6) + 5

pishuonlain [190]

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3 years ago

Maridel wants to find out how many of her classmates plan to come to the next football game. There are 800 students in her schoo

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Answer:

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3 years ago

Read 2 more answers

A candy store has ten giant pieces of candy! Find the probability of each event. There are 4 gumdrops, 3 lolipops, 2 jellybeans,

AveGali [126]

Answer:

1. P = 9/90 = 1/10

2. P = 16/90 = 8/45

3. P = 10/90 = 1/9

4. P = 4/90 = 2/45

Step-by-step explanation:

Total no. of candy = 10

No. of Gumdrops = 4

No. of Lollipops = 3

No. of Jellybeans = 2

No. of Peppermint = 1

1. To find the probability that the child will pick a peppermint or jellybean, we will add the probabilities of both the candies.

P(Peppermint) = No. of Peppermint/Total no. of candy

= 1/10

P(Jellybean) = No. of Jellybean/Total no. of candy

= 2/10

P(Peppermint or Jellybean) = 1/10 + 2/10

P(Peppermint or Jellybean) = 3/10

Then, the child picks a lollipop. Note that after picking a peppermint or a jellybean, the number of candies left are 9. So,

P(Lollipop) = No. of Lollipops/Total no. of candy

P(Lollipop) = 3/9

To compute the probability that the child will pick a peppermint or a jellybean and then a lollipop,

P = P(Peppermint or Jellybean) x P(Lollipop)

= 3/10 x 3/9

P = 9/90 = 1/10

2. Probability that a child will pick a lollipop or peppermint:

P(Lollipop or Peppermint) = P(lollipop) + P(peppermint)

= 3/10 + 1/10

P(Lollipop or Peppermint) = 4/10

Then the child picks a gumdrop. Note that the number of candies remaining are 9. So,

P(Gumdrop) = 4/9

The probability that the child picks a lollipop or peppermint and then a gumdrop:

P = P(Lollipop or Peppermint) x P(Gumdrop)

= 4/10 x 4/9

P = 16/90 = 8/45

3. Probability that a child will pick a jellybean:

P(Jellybean) = No. of Jellybeans/Total no. of candy

P(Jellybean) = 2/10

Then the child picks a peppermint or a gumdrop. Note that one candy has been picked out so there are 9 candies left in total.

P(Peppermint or Gumdrop) = P(peppermint) + P(Gumdrop)

= 1/9 + 4/9

P(Peppermint or Gumdrop) = 5/9

The probability that a child picks a jellybean then a peppermint or a gumdrop is:

P = P(Jellybean) x P(Peppermint or Gumdrop)

= 2/10 x 5/9

P = 10/90 = 1/9

4. P(peppermint) = 1/10

Then the child picks a gumdrop. (remaining candies are 9)

P(Gumdrop) = 4/9

Probability that a child will pick a peppermint then a gumdrop:

P = P(peppermint) x P(gumdrop)

= 1/10 x 4/9

P = 4/90 = 2/45

5 0

3 years ago