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mart [117]
4 years ago
5

Assume that the classes listed in the Java Quick Reference have been imported where appropriate.

Computers and Technology
1 answer:
Neko [114]4 years ago
7 0

The following java code will be written for the prescribed

<u>Explanation:</u>

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

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Yes, it is true, because it informs you

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Write the method makeNames that creates and returns a String array of new names based on the method’s two parameter arrays, arra
Gwar [14]

Answer:

  1. import java.util.Arrays;
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        String [] first = {"David", "Mike", "Katie", "Lucy"};
  5.        String [] middle = {"A", "B", "C", "D"};
  6.        String [] names = makeNames(first, middle);
  7.        System.out.println(Arrays.toString(names));
  8.    }
  9.    public static String [] makeNames(String [] array1, String [] array2){
  10.           if(array1.length == 0){
  11.               return array1;
  12.           }
  13.           if(array2.length == 0){
  14.               return array2;
  15.           }
  16.           String [] newNames = new String[array1.length];
  17.           for(int i=0; i < array1.length; i++){
  18.               newNames[i] = array1[i] + " " + array2[i];
  19.           }
  20.           return newNames;
  21.    }
  22. }

Explanation:

The solution code is written in Java.

Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).

In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]

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I want to know why almost every single "expert answer verified" thing I come across is wrong. If it's wrong, why the h is it exp
Studentka2010 [4]

Answer:

Because people just give out the verified things to the first person to answer their question

Explanation:

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