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hodyreva [135]
3 years ago
14

25x - 20y= -100 x-intercept:__________ y-intercept:__________

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

X = (-4, 0)

Y = (0, 5)

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A store sells small notebooks for ​$6 and large notebooks for ​$12. If a student buys 6 notebooks and spends ​$60​, how many of
a_sh-v [17]
He would have bought 2 small notebooks and 4 large notebooks. because $12×4= $48 and $6* 2 = $12. $48+$12=$60
8 0
3 years ago
Read 2 more answers
HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
3 years ago
Find the domain and range of the graph
asambeis [7]

Answer:

domain= -1, 3

range = -1, 1

Step-by-step explanation: ok

4 0
3 years ago
A rectangular tank that is 2048 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
ira [324]

Answer:

The box should have base 16ft by 16ft and height 8ft Therefore,dimensions are 16 ft by 16 ft by 8 ft

Step-by-step explanation:

We were given the volume of the tank as, 2048 cubic feet.

Form minimum weight, the surface area must be minimum.

Let the height be h and the lengths be x

the volume will be: V=x²h then substitute the value of volume, we have

2048=hx²

hence

h=2048/x²

Since the amount of material used is directly proportional to the surface area, then the material needs to be minimized by minimizing the surface area.

The surface area of the box described is

A=x²+4xh

Then substitute h into the Area equation we have

A= x² + 4x(2048/x²)

A= x² + 8192/x

We want to minimize

A

dA/dx = -8192/x² + 2 x= 0 for max or min

when dA/dx=0

dA/dx= 2x-8192/x²=0

2x=8192/x²

Hence

2x³=8192

x³=4096

x=₃√(4096)

X=16ft

Then h=2048/x²

h=2048/16²

h=8ft

The box should have base 16ft by 16ft and height 8ft

Hence the dimensions are 16 ft by 16 ft by 8 ft

8 0
3 years ago
Sebastian is going to deposit $790 in an account that earns 6.8% interest compounded annually his wife Yolanda will deposit $815
marissa [1.9K]

Answer: sorry dont know what to tell you im struggling too

Step-by-step explanation:

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4 0
3 years ago
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