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Nana76 [90]
3 years ago
12

Slope of (-5,3)(2,1)​

Mathematics
2 answers:
marin [14]3 years ago
7 0
Answer: -2/7

Slope is change in Y over change in X

Change in y: 1-3 = -2
Change in x = 2-(-5) = 7
Ilya [14]3 years ago
5 0

Answer:

slope =y2-y1/(x2-x1)

=1-3/(2-(-5)

= -2/7

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The constant of proportionality has the same value as the unit rate true or false?
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Answer:

True they represent the same thing

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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,
valentina_108 [34]
 2x2 + 8x - 12 = 0
4 + 8x - 12 = 0
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8x = 8
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3 years ago
What property describes the number sentence 6+0=6
sergejj [24]
Additive identity because that is the property when you add something to 0 and get the same thing
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The graph of f(x)=cos(x) is transformed into a new function, g(x) , by stretching it vertically by a factor of 3 and shifting it
tresset_1 [31]

Answer:

g(x) = 3 cos (x+2)

Step-by-step explanation:

To transform functions use the following formula f(x) = a cos b(x -c) + d where:

  • a stretches the function vertically
  • b compresses or stretches it horizontally
  • c shifts the function left or right
  • d shifts the function up or down

Here a = 3 and c = 2.

So the new function is g(x) = 3 cos (x+2).

5 0
3 years ago
Help asap plssssssssss
Kryger [21]

Step-by-step explanation:

distance AB is (using Pythagoras with the coordinate differences between both points as sides and the distance as Hypotenuse = baseline of the triangle, the side opposite of the 90 degree angle):

distance² = (5 - -10)² + (7-2)² = 15² + 5² = 225 + 25 = 250

distance = sqrt(250)

to split this distance into a 3/2 ratio, we need actually 3+2=5 equal parts. and then AM gets 3 off these parts, and MB gets 2 of these parts.

so,

distance/5 = sqrt(250)/5 = sqrt(250/25) = sqrt(10)

so,

AM = 3×sqrt(10) = sqrt(90),

and

MB = 2×sqrt(10) = sqrt(40)

now, we need to calculate back using the same Pythagoras approach (calling the coordinates of M xm and ym)

AM² = (xm - -10)² + (ym - 2)² = (xm+10)² + (ym-2)² = 90

90 = xm² + 20xm + 100 + ym² - 4ym + 4

MB² = (5 - xm)² + (7 - ym)² = 40

40 = 25 - 10xm + xm² + 49 - 14ym + ym²

as a first approach we calculate AM² - MB²

90 = xm² + 20xm + ym² - 4ym + 104

- 40 = xm² - 10xm + ym² - 14ym + 74

----------------------------------------------------

50 = 0 + 30xm + 0 + 10ym + 30

20 = 30xm + 10ym

2 = 3xm + ym

ym = 2 - 3xm

this we use now e.g. in the first equation for AM.

90 = xm² + 20xm + (2-3xm)² - 4×(2-3xm) + 104

-14 = xm² + 20xm + 4 - 12xm + 9xm² - 8 + 12xm

-10 = 10xm² + 20xm

-1 = xm² + 2xm

xm² + 2xm + 1 = 0

solving such a squared equation

xm = (-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = 2

c = 1

xm = (-2 ± sqrt(4 - 4))/2 = -1

only one combined solution (as a squared equation usually has 2 solutions).

ym = 2 - 3xm = 2 - 3×-1 = 2 + 3 = 5

so, M = (-1, 5)

8 0
2 years ago
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