Write an equation for the circle with center(-1,-5) and Radius 4sqrt3
1 answer:
Answer:
(x + 1)² + (y + 5)² = 48
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 1, - 5) and r = 4, so
(x - (- 1))² + (y - (- 5))² = (4 )², that is
(x + 1)² + (y + 5)² = 48 ← equation of circle
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Answer:
Step-by-step explanation:
This is written in the standard form of a quadratic function:
where:
- ax² → quadratic term
- bx → linear term
- c → constant
You need to convert this to vertex form:
where:
- (h,k) → vertex
To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:
Using your original equation, identify the a, b, and c terms:
Insert the known values into the equation:
Simplify. Two negatives make a positive:
X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:
Simplify using PEMDAS:
The value of y is -6 (3,-6). Insert these values into the vertex form:
Insert the value of a and simplify:
:Done