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dimaraw [331]
3 years ago
15

Write an equation for the circle with center(-1,-5) and Radius 4sqrt3

Mathematics
1 answer:
irina [24]3 years ago
7 0

Answer:

(x + 1)² + (y + 5)² = 48

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 1, - 5) and r = 4\sqrt{3}, so

(x - (- 1))² + (y - (- 5))² = (4\sqrt{3} )², that is

(x + 1)² + (y + 5)² = 48 ← equation of circle

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WILL GIVE BRAINLIEST!!!!
krek1111 [17]

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Question 1:

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Therefore, the slope is 2 5/12 or 29/12.

Question 2:

= 12-(-19)/-9-16

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Question 3:

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2 years ago
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larisa86 [58]

Answer:

x = 0

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
How would you write 2x^2-7=11 in both quadratic property and square root property?
dangina [55]

Answer:

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Step-by-step explanation:

Quadratic Property or a quadratic Function is of the form ax^2+bx+c=0. So our task is to equate the given expression to zero. We can equate the expression to zero by subtracting 11 on both the sides. In doing so, we get 2x^2-18=0. This is the quadratic Property of the given Expression.

Square property is finding the value for x. we have make x equal to some value. Since we already have the quadratic Property as 2x^2-18=0, we can use this to find the value of x.

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3 years ago
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3 years ago
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