If the axis of symmetry is x=-1, the vertex will have x-coordinate -1.
The point (0, 5) cannot be the vertex. The friend is not correct.
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If the point (1, 5) is on the graph so is the image of that point when it is reflected across the axis of symmetry. That image point is (-3, 5). A parabola that goes through points (1, 5) and (-3, 5) will not go through point (0, 5).
<h3>Answer:</h3>
D
<h3>Explanation:</h3>
The graph of |x| opens upward. Your graph is vertically stretched by a factor of 3 and translated downward 1 unit.
Graphs B and D open upward, but only graph D is translated downward (not upward, as in B).
There is no horizontal asymptote.
Answer: 1.25
Step-by-step explanation:
Convert it lol I don’t know how to say it? But also you can look it up if needed
