Answer:
![1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}](https://tex.z-dn.net/?f=1.%20%5Cquad%5Cdfrac%7B1%7D%7Bk%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5C%5C%5C%5C2.%20%5Cquad%5Csqrt%5B7%5D%7Bx%5E5%7D%5C%5C%5C%5C3.%20%5Cquad%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7By%5E2%7D%7D)
Step-by-step explanation:
The applicable rule is ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
It works both ways, going from radicals to frational exponents and vice versa.
The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.
<em>-3x-y=10</em>
<em>4x-4y=8</em>
<em>or</em>
<em>y = -3x - 10 </em>
<em>P(0,-10) and P(-2, -4) on this line: Plot and connect with the Line.</em>
<em></em>
<em> </em>
<em>y = x - 2</em>
<em>P(0, -2) and (2,0) on this line: Plot and connect with the Line.</em>
<em>P(-2,-4) is the ordered pair that is the solution for this system of EQs</em>
<em>On may CHECK by substituting x= -2 and y = -4 into the EQs of these Lines</em>
<em></em>
<em>Hope this helps!!!</em>
Answer:
62.8
Step-by-step explanation:
V = πr²h
V = 3.14 × 2² × 5
V = 3.14 × 4 × 5
V = 3.14 × 20
V = 62.8
Simply solve for x. Divide both sides by -3. Since you are dividing by a negative, flip the inequality sign. This gives you x<-2.
Note that the answer is x is less than or equal to -2. I am unable to insert the correct symbol on my keyboard.
Answer:b
Step-by-step explanation:
