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Blababa [14]
3 years ago
9

Can someone answer this question please answer it correctly if it’s correct I will mark you brainliest

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

21

Step-by-step explanation:

Area to be covered:

(6.25 + 1.5)(6.25 + 2(1.5)) - 6.25²

= 32.625

Each title's area = 0.25² = 0.0625

No. of tiles needed:

32.625 ÷ 0.0625

= 522

25 in each pack

522/25 = 20.88

So 21 packets

TEA [102]3 years ago
7 0

First, let's find the area of the patio:

6.25 * 6.25 = 39.0625

Next, we need to find the area of the patio and extension combined:

We know that the patio is now 3m wider and 1.5m longer.

(6.25 + 3) * (6.25 + 1.5)

9.25 * 7.75 = 71.6825

Then, we need to find the area of the extension alone, which can be done by subtracting the area of the patio from the area of the patio and extension combined:

71.6825 - 39.0625 = 32.625

Now, find the area of one tile:

0.25 * 0.25 = 0.0625

And divide the area of the extension by the area of one tile to find the number of tiles needed to build the extension:

32.625 / 0.0625 = 522

Divide the total number of tiles by 25 and round up to the nearest whole number to find the number of packages:

522 / 25 = 20.88

20.88 rounds up to 21 packages of tiles.

Ellis needs 21 packages of tiles.

Hope this helps!! :)

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nikdorinn [45]

Answer:

  1. The lowest value of the confidence interval is 0.5262 or 52.62%
  2. The highest value of the confidence interval is 0.5538 or 55.38%

Step-by-step explanation:

Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.

The general expression to apply here is;

C.I=p+-z*\sqrt{\frac{p(1-p)}{n} }

where ;

p=sample proportion

n=sample size

z*=value of z* from the standard normal distribution for 95% confidence level

Given;

n=5000

<u>Find p</u>

From the question 54% of people chosen said they did not have children under 18 living at home

\frac{54}{100} *5000 = 2700\\\\p=\frac{2700}{5000} =0.54

<u>To calculate the 95% confidence interval, follow the steps below;</u>

  • Find the value of z* from the z*-value table

The value of z* from the table is 1.96

  • calculate the sample proportion p

The value of p=0.54 as calculated above

  • Find p(1-p)

0.54(1-0.54)=0.2484

  • Find p(1-p)/n

Divide the value of p(1-p) with the sample size, n

\frac{0.2448}{5000} =0.00004968

  • Find the square-root of p(1-p)/n

=\sqrt{0.00004968} =0.007048

  • Find the margin of error

Here multiply the square-root of p(1-p)/n by the z*

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The 95% confidence interval for the lower end value is p-margin of error

=0.54-0.0138=0.5262

The 95% confidence interval for the upper end value is p+margin of error

0.54+0.0138=0.5538

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