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3 years ago

Which inequality will have a shaded area below the boundary line?

1 answer:

7 0

Another twofer !

We don't know what the choices are, and we don't know where
the boundary line is. Otherwise, the question is intriguing indeed.

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Show that f(x) f(y) - f(x+y), where f(x)= [cos x - sin x o] [sin x cos x o] [o o 1]

Naddik [55]

Answer:

The answer is below

Step-by-step explanation:

Show that f(x) f(y) = f(x+y)

From trigonometric:

sin(x + y) = sinxcosy + cosxsiny

sin(x - y) = sinxcosy - cosxsiny

cos(x + y) = cosxcosy - sinxsiny

cos(x - y) = cosxcosy + sinxsiny

$f(x)=\left[\begin{array}{ccc}cosx&-sinx&0\\sinx&cosx&0\\0&0&1\end{array}\right] ,f(y)=\left[\begin{array}{ccc}cosy&-siny&0\\siny&cosy&0\\0&0&1\end{array}\right] \\\\\\f(x)f(y)=\left[\begin{array}{ccc}cosxcosy-sinxsiny&-cosxsiny-sinxcosy&0\\sinxcosy+cosxsiny&-sinxsiny+cosxcosy&0\\0&0&1\end{array}\right] \\\\\\f(x)f(y)=\left[\begin{array}{ccc}cos(x+y)&-sin(x+y)&0\\sin(x+y)&cos(x+y)&0\\0&0&1\end{array}\right] \\\\\\$

$f(x+y)=\left[\begin{array}{ccc}cos(x+y)&-sin(x+y)&0\\sin(x+y)&cos(x+y)&0\\0&0&1\end{array}\right] \\\\\\Therefore\ f(x)f(y)=f(x+y)$

4 0

2 years ago

Which set of ordered pairs represents y as a function of x?

givi [52]

I think the answer is j

7 0

3 years ago

Find the circumference of each circle using the given radius or diameter. Round to the nearest hundredth when necessary.

Bezzdna [24]

43.98 yds
6.28 in
69.16 ft

7 0

3 years ago

Find the area 20 points!!!

Dmitriy789 [7]

Answer:

the answer would be 29 :)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

You start with a penny which doubles each day for 30 days. How much money would you have after 30 days?

Radda [10]

Answer:

$555,765.76

Step-by-step explanation:

128

256

512

1024

2048

4096

8192

16282

32564

65128

13256

26512

53024

106048

212096

424192

868384

1736768

3473536

6947072

13894144

27788288

55576576=

555,765.76

6 0

2 years ago