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1 answer:
Q3.
Answer:
Q4.
The horizontal line: y = a
Answer: y = 4
Q5.
x-intecept of Ax + By = C is that value of x for which y = 0
2x + 4y = -10
/subtitute y=0/
2x + 4 · 0 = -10
2x = -10 |divide both sides by 2
x = -5
Answer: (-5; 0)
Q6.
x = a is the vertical line
x = 5
Answer: Graph #4.
Q7.
6x - 4y = -8 |subtract 6x from both sides
-4y = -6x - 8 |divide both sides by (-4)
y = 1.5x + 2
y-intercept (0; 2)
1.5x + 2 = 0 |subtract 2 from both sides
1.5x = -2 |divide both sides by 1.5
x = -1 1/3
x-intercept (-1 1/3; 0)
Answer: Graph #3.
Answer:
Q4.
The horizontal line: y = a
Answer: y = 4
Q5.
x-intecept of Ax + By = C is that value of x for which y = 0
2x + 4y = -10
/subtitute y=0/
2x + 4 · 0 = -10
2x = -10 |divide both sides by 2
x = -5
Answer: (-5; 0)
Q6.
x = a is the vertical line
x = 5
Answer: Graph #4.
Q7.
6x - 4y = -8 |subtract 6x from both sides
-4y = -6x - 8 |divide both sides by (-4)
y = 1.5x + 2
y-intercept (0; 2)
1.5x + 2 = 0 |subtract 2 from both sides
1.5x = -2 |divide both sides by 1.5
x = -1 1/3
x-intercept (-1 1/3; 0)
Answer: Graph #3.
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Answer:
Step-by-step explanation:
Given that a particular detection system has a 0.83 probability of detecting a missile attack.
Also each system is independent of the other to detect missile attack.
a) the probability that a single detection system will detect an attack=
b) the probability that at least one of the systems will detect the attack given two systems= 1-Prob no system detects
=
c) If three systems are installed, the probability that at least one of the systems will detect the attack
= 1- none of the three systems detect attack
d) We find that probability of detecting is more if we increase the system form 1 to 2 and 2 to 3.
Hence for safety and defence purpose multiple detection system is recommended.