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3 years ago

What is/ how do you calculate the vertex for a parabola with this equation: y=-1x^2 13x?

1 answer:

4 0

Y=x^2+13x
complete the square to get it into form y=a(x-h)^2+k whre (h,k) is the vertex

y=x^2+13x
y=(x^2+13x)
13/2=6.5, 6.5^2=42.25
y=(x^2+13x+42.25-42.25)
y=((x+6.5)^2-42.25)
y=(x-(-6.5))^2+(-42.25)
the vertex is (-6.5,-42.25)

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3 years ago

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3 years ago

Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

iogann1982 [59]

Answer:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

$A_i = 7 in *5 in = 35in^2$

And we know that the initial area is a half of the entire area in red $A_i = \frac{A_f}{2}$ , so then:

$A_f = 2 A_ i =2*35 = 70$

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

$70 = (x+7) (x+5)$

We multiply both terms using algebra and the distributive property and we got:

$70 =x^2 +12 x +5$

And we can rewrite the expression like this:

$x^2 +12 x -35 = 0$

And we can solve this using the quadratic formula given by:

$x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where $a = 1, b =12 and c=-35$ if we replace we got:

$x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}$

And the two possible solutions are then:

$x_1 =-14.43 in, x_2 = 2.426in$

Since the measurement can't be negative the correct answer for this case would be $x =2.426 in$

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4 years ago

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Answer:

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3 years ago

A garden is shaped like a rectangle whose perimeter is 150 ft. The length is 2 times as long as the width. Find the length and t

vlabodo [156]

Answer:

Step-by-step explanation:

L=2W

P=2(L+W), using L=2W this becomes

P=2(2W+W)

P=2(3W)

P=6W, given P=150

6W=150

W=25, and since L=2W

L=50 so

L=50ft and W=25ft

6 0

3 years ago