Solve the equation for x-2020

Drag each tile to the correct box

ValentinkaMS [17]

Answer:

Arranging the solutions from the least to the highest;

1. 1.743 x 10⁻²

2. 3.626 x 10⁻²

3. 4.64 x 10⁻²

4. 3.162 x 10²

5. 4.214 x 10³

Step-by-step explanation:

The solutions of the mathematical expression are calculated as follows;

$1. \ \ (4.3\times 10^6)(9.8\times 10^{-4}) = (4.3\times 9.8\times 10^{6-4}) = (42.14\times 10^2)= 4.214 \times 10^3$

$2. \ \ (2.9\times 10^7)(1.6\times 10^{-9}) = (2.9\times 1.6\times 10^{7-9}) = 4.64\times 10^{-2}$

$3. \ \ \frac{(4.7 \times 10^3)(8.6\times 10^{-7})}{(3.8\times 10^{-4})(6.1 \times 10^2)} = \frac{(4.7\times 8.6\times 10^{3-7})}{(3.8\times 6.1\times 10^{-4+2})} = \frac{4.042 \times 10^{-3}}{2.318\times 10^{-1}} = 1.743\times 10^{-2}$

$4. \ \ (4.9\times 10^3)(7.4\times 10^{-6}) = (4.9\times 7.4\times 10^{3-6}) = 3.626\times 10^{-2}$

$5. \ \ \frac{(3.9 \times 10^5)(8.7\times 10^{-3})}{(3.7\times 10^{-5})(2.9 \times 10^8)} = \frac{(3.9\times 8.7\times 10^{5-3})}{(3.7\times 2.9\times 10^{-4 +8 })} = \frac{3.393 \times 10^{-1}}{1.073\times 10^{-3}} = 3.162\times 10^{2}$

Arranging the solutions from the least to the highest;

1. 1.743 x 10⁻²

2. 3.626 x 10⁻²

3. 4.64 x 10⁻²

4. 3.162 x 10²

5. 4.214 x 10³

4 0

3 years ago

Read 2 more answers

You cut a piece of paper and fold it into a square pyramid. Find the area of the paper. 3 in. 2 in. The area of the paper is not

Doss [256]

Comment:

Then how does that work

Step-by-step explanation:

5 0

3 years ago

The newest model of smart car is supposed to get excellent gas mileage. A thorough study showed that gas mileage (measured in mi

Anton [14]

Answer:

D. 1 – NORM.DIST(100, 75, 10, TRUE)

Step-by-step explanation:

Excel's Normal Distribution

The normal distribution has two parameters: the mean value $\mu$ and the standard deviation $\sigma$ . Since it's a symmetric function the values at the right side of the center value

The normal distribution is a function which integral cannot be expressed in terms of elemental functions. That is why the cumulative probability is usually found in tables, graphs or any digital media like Excel.

The formula NORM.DIST computes the cumulative values for the left tail or $P( X < X_o)$ for a given mean and standard deviation. The parameters are

$NORM.DIST (X_o,\mu,\sigma,cumulative)$

This last parameter tells the formula we want the cumulative left-tail probability or just the value at Xo. This value must be set to TRUE to compute the probability for a range of values, like in the problem at hand.

Since the formula computes the left-tail of the function, we must take advantage of the symmetry of the distribution if we want to compute right-tail values we just subtract the result from 1.

Thus, the correct formula to calculate the required probability is

D. 1 – NORM.DIST(100, 75, 10, TRUE)

3 0

3 years ago

If the first and the last terms of an arithmetic series are 10 and 62, show that the sum of the series varies directly as the nu

Nitella [24]

Answer:

10+^@=72_^) + the series

Step-by-step explanation:

6 0

3 years ago

In 2010, the Census Bureau estimated the proportion of all Americans who own their homes to be 0.669. An urban economist wants t

Alexxandr [17]

Answer:

i)

Sample size making use of the Census Bureau: 1,499 American adults.

Sample size without making use of the Census Bureau: 1,692 American adults

ii)

71

Step-by-step explanation:

i)

The sample size n in Simple Random Sampling is given by

$\bf n=\frac{z^2p(1-p)}{e^2}$

where

z = 1.645 is the critical value for a 90% confidence level (*) 

p= 0.669 is the population proportion given by the Census

e = 0.02 is the margin of error

so

$\bf n=\frac{(1.645)^2*0.669*0.331}{0.02^2}=1,498.05\approx 1,499$

rounded up to the nearest integer.

(*)This is a point z such that the area under the Normal curve N(0,1) 1nside the interval [-z, z] equals 90% = 0.9

It can be obtained with tables or in Excel or OpenOffice Calc with

NORMSINV(0.95)

If she ignores the Census estimate, the she has to take the largest sample possible that meets the requirements.

Let's show it is obtained when p = 0.5

As we said, the sample size n is

$\bf n=\frac{z^2p(1-p)}{e^2}$

where

e = 0.02 is the error proportion

z = 1.645

hence

$\bf n=\frac{(1.645)^2p(1-p)}{(0.02)^2}=6765.0625p(1-p)=6765.0625p-6765.0625p^2$

taking the derivative with respect to p, we get

n'(p)=6765.0625-2*6765.0625p

and

n'(p) = 0 when p=0.5

By taking the second derivative we see n''(p)<0, so p=0.5 is a maximum of n

This means that if we set p=0.5, we get the maximum sample size for the confidence level required for the proportion error 0.02

Replacing p with 0.5 in the formula for the sample size we get

$\bf n=6765.0625*0.5-6765.0625(0.5)^2=1691.27\approx 1,692$

rounded to the nearest integer.

ii)

When we do not have a proportion but a variable whose approximate standard deviation s is known, then the sample size n in Simple Random Sampling is given by

$\bf n=\frac{z^2s^2}{e^2}$

where

z = 2.241 is the critical value for a 95% confidence level (*) 

s = 7.5 is the estimated population standard deviation

e = 2 hours is the margin of error

so

$\bf n=\frac{z^2s^2}{e^2}=\frac{(2.241)^2(7.5)^2}{(2)^2}=70.62\approx 71$

(*)This is a point z such that the area under the Normal curve N(0,1) inside the interval [-z, z] equals 95% = 0.95

It can be obtained in Excel or OpenOffice Calc with

NORMSINV(0.9875)

5 0

4 years ago