Question

Solve each system of equation for 3y+x=3 and -2y+5x=15

Answer 1

Answer:

x = 3 and y = 0

Step-by-step explanation:

3y+x=3

-2y+5x=15

Isolate y in 3y + x = 3 :

$y=$ $\frac{3-x}{3}$

Substitute $y = \frac{3-x}{3}$  in -2y + 5x = 15 :

$-2 * \frac{3-x}{3} + 5x = 15$

Simplify the equation :

$\frac{-6+17x}{3} =15$

Isolate x in $\frac{-6 + 17x}{3} = 15$ :

Proving x = 3

Isolate y in $y = \frac{3-3}{3}$ :

Proving y = 0

Your solved system of equations are x being 3, and y being 0.