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3 years ago

A jet travels 580 miles in 5 hours. At this rate how far could the jet fly in 8 hours? What is the rate of speed of the jet

Mathematics

1 answer:

tankabanditka [31]3 years ago

8 0

928 miles the rate of speed is 116 miles

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What is the parabola’s line of symmetry? y-axis x-axis x = p x = -p

Licemer1 [7]

The parabola's line of symmetry is the x-axis.

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3 years ago

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Subtracting mixed number 4_1 - 2_7 4 8 4

aleksandr82 [10.1K]

Answer:

$4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}$

Step-by-step explanation:

Given

$4\frac{1}{4} - 2\frac{7}{8}$ --- proper representation of the question

Required

Evaluate

Convert numbers to improper fractions

$4\frac{1}{4} - 2\frac{7}{8} = \frac{17}{4} - \frac{23}{8}$

Take LCM

$4\frac{1}{4} - 2\frac{7}{8} = \frac{34 - 23}{8}$

$4\frac{1}{4} - 2\frac{7}{8} = \frac{11}{8}$

Convert to improper fraction

$4\frac{1}{4} - 2\frac{7}{8} = 1\frac{3}{8}$

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3 years ago

SOMEONE PLEASEEEEW HELP ME OUTTT

garik1379 [7]

Answer:

By Double splitting method

=> 2x²-7x+5

=> 2x²-2x-5x+5

=>2x(x-1)-5(x-1)

x=5/2
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3 years ago

Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf

erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

$(\overline{x}_1-\overline{x}_2)\pm t^*\times SE$ ,

where $(\overline{x}_1-\overline{x}_2)$ = sample mean difference .

$t^*$ = critical t value (two-tailed)

SE= Standard error.

Given : $(\overline{x}_1-\overline{x}_2)=23$

$t^*=2.262$

SE= 4.2

Now, the confidence interval for mean difference will be :-

$23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)$

Hence, the required confidence interval : (13.4996, 32.5004)

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2 years ago

Right angle trigonometry

Nady [450]

Answer:

Step-by-step explanation:

Given

sinΘ = $\frac{1}{\sqrt{2} }$ , then

Θ = $sin^{-1}$ ( $\frac{1}{\sqrt{2} }$ ) = 45° → B

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2 years ago