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attashe74 [19]
3 years ago
14

A jet travels 580 miles in 5 hours. At this rate how far could the jet fly in 8 hours? What is the rate of speed of the jet

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

928 miles the rate of speed is 116 miles
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write the equaion of a line in slope-intercept form if the slope is 1/5 and the y-intercept is -9 explain please
faust18 [17]

Answer:

y = \frac{1}{5} x - 9

Step-by-step explanation:

The slope-intercept form is y = mx + b, where:

m = slope

b = y-intercept.

The slope (m) tells you the steepness of the line. It is the average rate of change which measures how the y-value changes for each one-unit change in the x-value. Hence, slope = \frac{rise}{run}.  So the given slope of 1/5 means that for every 1 unit change in the y-value, the x-value changes by 5 units (you go up 1 unit, and "run" 5 units to the right).

Next, the y-intercept is the point on the graph where it crosses the y-axis, and has the coordinates, (0, b). It is also the value of y when x = 0. Since you're given the y-intercept of -9, then that means that it is the y-coordinate of (0, <em>b</em>). So, it becomes (0, -9).

Now that we have our slope (<em>m </em>) = 1/5, and the y-intercept (<em>b </em>) = -9, we can write the equation of the line as:

y = \frac{1}{5} x - 9

(I'm also including a screenshot of the line where it shows the y-intercept of (0, -9) on the graph).  

Please mark my answers as the Brainliest if you find my explanations helpful :)

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The graphed line can be expressed by which equation?
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What equation? Can’t really help you if there is no equation there
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Match each graph with its corresponding system of inequalities?
myrzilka [38]

It would be helpful to see the actual choices, but let me try to answer anyway:

(1) blue area:

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read area

y<-3


(2) blue:

y>3*x-3

red:

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E / c^2 = M.
to solve it, I just divided by c^2 on both sides because of the division property of equality.
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Please help<br> Solve the system by substitution:
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Multiply the first equation by negative 3 and then add that new equation to the second one
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