Answer : value of x and y in the matrix equation is:
x = -3
y = +4, -4
Step-by-step explanation :
The matrix expression is:
![\left[\begin{array}{ccc}x+4\\y^2+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B4%5C%5Cy%5E2%2B1%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-9x%5C%5C-17%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
First we have to add left hand side matrix.
![\left[\begin{array}{ccc}(x+4)+(-9x)\\(y^2+1)+(-17)\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28x%2B4%29%2B%28-9x%29%5C%5C%28y%5E2%2B1%29%2B%28-17%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Now we have to add left hand side terms.
![\left[\begin{array}{ccc}x+4-9x\\y^2+1-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B4-9x%5C%5Cy%5E2%2B1-17%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}4-8x\\y^2-16\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-8x%5C%5Cy%5E2-16%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D28%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Now we have to equating left hand side matrix to right hand matrix, we get:
Therefore, the value of x and y in the matrix equation is -3 and +4, -4 respectively.
Answer:
A exponential equation is usually of the form f(x)=a (1±r)ˣ.
Our limitation: Initial Vale is 500.
Let's look at our options:
#1- Initial Value of 1000 --- WRONG!
#2- Initial Value of 1000 --- WRONG!
#3- Initial Value of 500 ---- Maybe
#4- Initial Value of 500 ---- Maybe
Let's look at 3 and 4:
#3- Fits Our Form of f(x)=a (1±r)ˣ ---- CORRECT!
#4- Does not fit Our Form of f(x)=a (1±r)ˣ, It's to the 2nd power, not the x power! ---- WRONG!
Hence, #3 Is correct!
Step-by-step explanation:
Well, I hope you understood, and I'd gladly explain anything that didn't make sense. A brainliest would be appreciated, thank you!
-Zylynn Jade Ardenne
Answer:
y = 5
Step-by-step explanation:
y = 0x + b
5 = 0(4) + b
5 = 0 + b
5 = b
I think it's none because that should be communitive and that's not there so.
