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3 years ago

4.11.1 Practice: Assignment. Please help i will mark brainliest!

Mathematics

2 answers:

padilas [110]3 years ago

6 0

Step-by-step explanation:

1.x^2+7x+12

find two numbers that multiply to give the constant by the coefficient of x squared and when added will give you 7 x . the numbers are 3 and 4

(x^2+4x)+(3x+12)

x(x+4)+3(x+4)

(x+4) and(x+3) are the factors

2.4x^2+6x+2

(4x^2+2x)+(4x+2)

2x(x+1)+2(x+1)

(x+1) and(2x+2) are the factors.

amm18123 years ago

5 0

Step-by-step explanation:

x2 + 7x + 12

x2 + 4x + 3x + 12

x(x + 4) + 3( x + 4)

(x + 3) and (x + 4) are the factors

4x2 + 6x + 2

4x2 + 4x + 2x + 2

4x (x + 1) + 2(x + 1)

(x + 1) and (4x + 2) are the factors

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Brielle is making a mosaic picture that is ¼ foot by ¾ foot. What is the area of her mosaic?

fenix001 [56]

1/4 x 3/4 = 3/16 ft squared

6 0

2 years ago

1. What does it mean for a number to have a variable at the end of it? (i.e 1.6x)

miskamm [114]

Answer:

1. 1.6x has a variable which means an unknown number

2. 5 more than 0.10 times a number

Step-by-step explanation:

A variable is an unknown number represented by a letter. It provides a way to write a relationship in the real world without knowing all the values involved, 1.6x means 1.6 times an unknown number mathematically. A real world example would be a percent growth of 60% on an unknown price - 1.6x.

5 + 0.10x means 5 more than 0.10 times an unknown number. A real world example here would be "10% off a sale plus $5 coupon". We don't know the price of the item but we do know it is 10% off and we get $5 off. Once we know the price we input it int for x and find the total discount.

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3 years ago

Given : If You are at least 25 years Old Then you can rent a car

KIM [24]

Answer:

Law of Syllogism

Step-by-step explanation:

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2 years ago

6. On a bank account of $2,500, how much yearly interest will be paid if the rate is3.4%?

iVinArrow [24]

Multiply the amount in the account by the interest rate:

2500 x 0.034 = 85.00

Answer: $85.00

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2 years ago

4.11.1 Practice: Assignment. Please help i will mark brainliest! ​

4.11.1 Practice: Assignment. Please help i will mark brainliest!