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Ugo [173]
3 years ago
11

4.11.1 Practice: Assignment. Please help i will mark brainliest! ​

Mathematics
2 answers:
padilas [110]3 years ago
6 0

Step-by-step explanation:

1.x^2+7x+12

find two numbers that multiply to give the constant by the coefficient of x squared and when added will give you 7 x . the numbers are 3 and 4

(x^2+4x)+(3x+12)

x(x+4)+3(x+4)

(x+4) and(x+3) are the factors

2.4x^2+6x+2

(4x^2+2x)+(4x+2)

2x(x+1)+2(x+1)

(x+1) and(2x+2) are the factors.

amm18123 years ago
5 0

Step-by-step explanation:

x2 + 7x + 12

x2 + 4x + 3x + 12

x(x + 4) + 3( x + 4)

(x + 3) and (x + 4) are the factors

4x2 + 6x + 2

4x2 + 4x + 2x + 2

4x (x + 1) + 2(x + 1)

(x + 1) and (4x + 2) are the factors

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Carol buys a house for £234 900
Aneli [31]

Answer:

23,490

Step-by-step explanation:

10% = 0.1

234900 x 0.1 = 23490

3 0
3 years ago
A rabbit population doubles every 4 weeks.There are currently five rabbits in a restricted area. If t represents the time in wee
sertanlavr [38]
Doubling formula is this:

P(t)=P(2)^{\frac{t}{d}}
where P=initial number of rabbits
t=time
d=time it takes to doulbe

ok, so 4 weeks is the doubling time so that is 4*7=28 days

we wawnt time=98
and oroiginal number of rabbits is 5 so
P(98)=5(2)^{\frac{98}{28}}
P(98)=5(2)^{3.5}
P(98)=5(2^3)(\sqrt{2})
P(98)=5(8)\sqrt{2}
P(98)=40\sqrt{2}
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days
8 0
4 years ago
Rearrange to make x the subject<br> 4(x-3) =y<br> pls help
Alina [70]
4(-3x)=y F f f f f f f f d d d d d d d d d d d d d d d d d d d d d d
3 0
2 years ago
Is 9.707 greater than 9.717
stepan [7]
No 9.717 is greater than 9.707 because 9.717 would be seven hundred seven thousandths and 9.717 would be seven hundred seven teen hundredths.
8 0
3 years ago
There are nine men and ten women in a club; in how many ways can a committee of four be formed?
DochEvi [55]
There are 19 people total, and groups of four are being asked of us. We can use the formula for permutations or combinations.

Permutations: \frac{n!}{(n-r)!}
Combinations: \frac{n!}{r!(n-r)!}
Where in both scenarios, there are <em>n</em> objects being chosen at <em>r</em> times.

19 P 4 is 93024
19 C 4 is 3876
It all depends on whether order matters with group placement; if it does, your answer is 93024, if not, then your answer is 3876.

:)
8 0
3 years ago
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