Well if y represents the vertical distance of the ball then you want to solve the equation for when y is 0, since 0 would represent the ball being on the ground. So substitute 0 in for y and solve the equation.
0 = - 0.001x^2 + 0.3x
we have a common factor of x in both terms so we can take that out.
0 = x(-0.001x + 0.3)
Zero product property tells us that we can set both of those products equal to zero and solve
0 = x
0 = -0.001x + 0.3
our first answer is x = 0 is obvious bc thats when the ball starts before you hit it, means it traveled 0.
solving the second equation gives us x = 300
so the ball traveled 300 "yards" I suppose your problem starts, which is impossible, but no matter thats the answer :-)
P(x)=f(x)*g(x)
P(x)=(x-400)(1,200-2x)
P(x)=1,200x-2x^2-480,000+800x
P(x)=-2x^2+2,000x-480,000
Answer: Option <span>D. P(x) = -2x2 + 2,000x - 480,000</span>
Answer:
an = 1/2 (4)^ (n-1)
a6 = 512
Step-by-step explanation:
The formula for a geometric sequence is
an = a1 (r)^(n-1)
where an is the term of the sequence
a1 is the initial term of the sequence
r is the ratio
and n is the term number
We know a1 = 1/2 and r =4
I will assume that x=6 means we want to know the 6th term
an = 1/2 (4)^ (n-1)
We want to find the 6th term
a6 = 1/2 * 4^(6-1)
a6 = 1/2 * 4^5
a6 = 512
