What is the distnace between. The following 2 points (-4,14)and (4,8)

Mathematics

1 answer:

alexdok [17]3 years ago

7 0

The distance between those two points is 28

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The area of a rectangle is greater than 60 ft. The width of the rectangle is 2x - 3 ft and the

34kurt

Answer:

Inequaliy: 2x-3(12)>60

X>48

Step-by-step explanation:

Since area of a rectangle is W(L)=A

The inequality given right here including length And width and area Plugged in would be

2x-3(12)>60. (It’s >60 because the area stated in the problem said to be greater then 60 so we put a Greater then sign)

Combine like terms and solve

2x-36>60

Add 36 on both sides

2x>96

Divide 2 on both sides to isolate variable

x>48

Check:

2(50)-36>60 ( I used 50 because it’s greater then 48 and it’s a easy number to work with for just a check)

solve:

100-36>60

64>60✔️

7 0

3 years ago

Cynthia invests some money in a bank which pays 5% compound interest per year. She wants it to be worth over £8000 at the end of

Agata [3.3K]

$\bf \qquad \textit{Compound Interest Earned Amount}\\\\A=P\left(1+\frac{r}{n}\right)^{nt}\quad \begin{cases}A=\textit{accumulated amount}\to &8000\\P=\textit{original amount deposited}\\r=rate\to 5\%\to \frac{5}{100}\to &0.05\\n=\begin{array}{llll}\textit{times it compounds per year}\\\textit{is only once, so}\end{array}\to &1\\t=years\to &3\end{cases}$

$\bf 8000=P\left(1+\frac{0.05}{1}\right)^{1\cdot 3}\implies 8000=P(1.05)^3\implies \cfrac{8000}{1.05^3}=P\\\\\\6910.70\approx P\implies \stackrel{\textit{rounded up}}{6911 = P}\qquad therefore\qquad 6911~~\leqslant ~~P$