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frosja888 [35]
3 years ago
10

Please, help me. What is it.

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

5^36

Step-by-step explanation:

5^4^9

A power to a power is found by multiplying the exponents

a^b^c = a^ ( b*c)

5^(4*9)

5^36

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You see a news headline which claims that tuition at CSU San Jose is going to increase by 7% next year. If tuition for in-state
wolverine [178]

The tuition would be $6143.94 next year

<h3>How to detemrine the tuition amount?</h3>

The given parameters are:

  • Current amount = $5,742
  • Rate of increment, r = 7%

The tuition next year is then calculated as:

Tuition = Current * (1 + Rate)

This gives

Tuition = $5,742 * (1 + 7%)

Evaluate

Tuition = $6143.94

Hence, the tuition would be $6143.94 next year

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6 0
2 years ago
What is the term-to-term rule for this sequence?<br> 64, 32, 16, 8, 4
just olya [345]

Answer:

a n=1/2 an - 1

Step-by-step explanation:

64,32,16,8,4. is a geometric sequence. this is a sequence where, to get from one term to the next, there is a number that you have to multiply it by. this is the same for all parts of the sequence.

4 0
3 years ago
Please help ASAP I’m confused<br><br> I WILL GIVE BRAINLIEST
neonofarm [45]

Answer: x=4.7434

Step-by-step explanation:

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plug in and solve

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4x^{2} =90

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if you need to solve for the sides

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7 0
3 years ago
Which of the following points lies on the circle whose center is at the origin and whose radius is 13?
Alexxandr [17]

any point that is on the circle will  have a distance of "radius" units, namely 13 units, since the radius is just that.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{origin}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{12})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-5-0)^2+(12-0)^2}\implies d=\sqrt{(-5)^2+12^2} \\\\\\ d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13

8 0
3 years ago
What is limit of (x cubed 3 x squared 4 x minus 12) as x approaches negative 3? –78 –24 30 54
Sergio039 [100]

The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

x^3 + 3x^2 + 4x - 12

As x approaches -3.

The limit expression becomes

\lim_{x \to -3} x^3 + 3x^2 + 4x - 12

Substitute -3 for x in the expression

\lim_{x \to -3} (-3)^3 + 3(-3)^2 - 4*3 - 12

Evaluate the expression

\lim_{x \to -3} -24

Hence, the limit of the expression as x approaches -3 is -24

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7 0
2 years ago
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