Is 4/5 an integer? pls help

20c + 8d +10c - 5d please answer you would get 15 points!

Rudik [331]

I think 30c+3d would be the correct answer.

4 0

2 years ago

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No pic/link just type answer pls.

Aleksandr-060686 [28]

I got 4.42 hope this helps:)

7 0

3 years ago

Select the correct answer from the drop-down menu. Shapes I and II are

dexar [7]

Answer:

similar but not congruent

Step-by-step explanation:

5 0

3 years ago

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1.08t can be written as (1.081/12)12t to give the approximate equivalent monthly interest rate based on an annual rate of 8%. Us

kobusy [5.1K]

Because t is given in years and 1.08 = 1 + 0.08, the annual percent increase
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = $\frac{1}{12} * 12 t$ 
and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.

$1.08^{t} 
= 1.08^{(1/12)(12t)} 
= (1.08^{1/12}) ^{12t} 
= 1.0064634^{12t}$

6 0

2 years ago

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A crossover trial is a type of experiment used to compare two drugs. Subjects take one drug for a period of time and then switch

zysi [14]

Answer:

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369$

$df=n-1=7-1=6$

$p_v =2*P(t_{(6)}$

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

Step-by-step explanation:

We have the following info given by the problem

Subject 1 2 3 4 5 6 7

Drug A 6 3 4 5 7 1 4

Drug B 5 1 5 5 5 2 2

x=value for drug A , y = value for drug B

x: 6 3 4 5 7 1 4

y: 5 1 5 5 5 2 2

We want to verify if the mean response differs between the two drugs then the system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x = 0$

Alternative hypothesis: $\mu_y -\mu_x \neq 0$

We can begin calculating the difference $d_i=y_i-x_i$ and we obtain this:

d: -1, -2, 1, 0, -2, 1, -2

Now we can calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.714$

Now we can find the the standard deviation for the differences, and we got:

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}}=1.38$

And now we can calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369$

Now we can find the degrees of freedom given by:

$df=n-1=7-1=6$

We can calculate the p value, since we have a two tailed test the p value is given by:

$p_v =2*P(t_{(6)}$

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

7 0

3 years ago