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serious [3.7K]
3 years ago
8

A cable is tied to the of a flagpole and it is connected to the ground 6 yards away from the base of the . If the flagpole is 8

yards high, how long is the cable?
Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

10 yard

Step-by-step explanation:

here... imagine...

flag pole. is perpendicular to the ground and is 8 yards high...

so ...

we can form right angled triangle having hypotenuse .. which is rope...

so by pythagoras theorem...

h =

\sqrt{p{ }^{2} + b {}^{2}   }

so... it would be...

\sqrt{6 { }^{2}  + 8 {}^{2} }

i.e.. 10

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Find the equation of the line passing through the point (–1, 0) and parallel to the line y = –1∕2x + 3∕7
PilotLPTM [1.2K]

Answer:

y = -1/2x - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step 1: Define

y = -1/2x + 3/7

Point (-1, 0)

Step 2: Find parallel line

<em>Parallel lines have the same slope as the original but different y-intercepts.</em>

<em>m</em> = -1/2

y = -1/2x + b

0 = -1/2(-1) + b

0 = 1/2 + b

b = -1/2

Step 3: Write parallel line

y = -1/2x - 1/2

7 0
3 years ago
After the 30% discount was applied, Patricia paid $45.50 for the ring. What was the original price of the ring
romanna [79]
45.50*.30 = 13.65
13.65+45.50 = 59.15 
3 0
3 years ago
Please help I need help
aliina [53]
It think the answer could quite possibly be 4
8 0
3 years ago
The length of a rectangle is 5 feet and the width is 8 feet.what is the area of the rectangle​
aliya0001 [1]

Answer:

40 ft squared

Step-by-step explanation:

To calculate area of a rectangle, you use the formula length times width, or base times height.

5 x 8 = 40 feet squared

5 0
3 years ago
Please answer me question 3 solving part​
Illusion [34]

Answer:

1. D

2. B

3. A

Step-by-step explanation:

Question 1:

The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.

Question 2:

Given that <KLM = x°

<KML = 50°

<JKL = (2x - 15)°

According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.

2x - 15 = x + 50

Solve for x

2x - x = 15 + 50

x = 65

Therefore, <KLM = 65°

QUESTION 3:

<JKL = 2x - 15

Plug in the value of x

<JKL = 2(65) - 15

= 130 - 15

<JKL = 115°

7 0
3 years ago
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