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ICE Princess25 [194]
2 years ago
15

Find the Size of angle YZX give your answer to 3 significant figures

Mathematics
1 answer:
rewona [7]2 years ago
3 0

Answer:

19.7degrees

Step-by-step explanation:

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What are these questions i need help
Over [174]

The roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

<h3>What are quadratic equations?</h3>

Quadratic equations are equations that have a second degree and have the standard form of ax^2 + bx + c = 0, where a, b and c are constants and the variable a does not equal 0

<h3>How to determine the other roots of the equation?</h3>

The equation of the function is given as:

f(x) = x^2 - 93987

The above equation is a quadratic equation

Express the equation as a difference of two squares

f(x) = (x - √93987)(x + √93987)

Set the equation of the function to 0

(x - √93987)(x + √93987) = 0

Split the factors of the above function equation as follows

x - √93987 = 0 and x + √93987 = 0

Solve for x in the above equations

x = √93987 and x = -√93987

Hence, the roots of the equation f(x) = x^2 - 93987 are x = √93987 and x = -√93987

Read more about roots of equation at

brainly.com/question/776122

#SPJ1

5 0
1 year ago
Make q subject of the formula 2(q+p) = 1+5q
m_a_m_a [10]

Answer:

expand the equation

then make q the subject of the formal

6 0
2 years ago
31.Helppoo with 31. Work and explanation of why
kow [346]
The answer is C. $47.22
3 0
3 years ago
Find all solutions in the interval [0, 2π). tan x + sec x = 1
svp [43]
Use the identity 
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x  = 1 + tan^2x - 2 tan x
0 = -2 tanx 

tan x = 0 

x =  0, π 
π is an extraneous root because sec 180 = -1 
So the answer  is 0 degrees
6 0
3 years ago
Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2
Phoenix [80]

Answer:

B

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = \sqrt{3} , then letting the altitude be h

tan60° = \frac{opposite}{adjacent} = \frac{11\sqrt{6} }{h}  = \sqrt{3} ( multiply both sides by h )

11\sqrt{6} = h × \sqrt{3} ( divide both sides by \sqrt{3} )

11\sqrt{2} = h

using the sine ratio in the triangle on the left and the exact value

sin45° = \frac{\sqrt{2} }{2} , then

sin45° = \frac{opposite}{hypotenuse} = \frac{h}{x} = \frac{11\sqrt{2} }{x} = \frac{\sqrt{2} }{2} ( cross- multiply )

\sqrt{2} × x = 22\sqrt{2} ( divide both sides by \sqrt{2} )

x = 22

6 0
1 year ago
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