What is your assignment about
two me plus you equals one <3
Answer:
The answer to your question is the second option 
Step-by-step explanation:
Expression
![[\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28x%5E%7B2%7Dy%5E%7B3%7D%29%5E%7B-2%7D%7D%7B%28x%5E%7B6%7Dy%5E%7B3%7Dz%29%5E%7B2%7D%7D%5D%5E%7B3%7D)
Process
1.- Divide the fraction in numerator and denominator
a) Numerator
[(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸
b) Denominator
[(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶
2.- Simplify like terms
a) x⁻¹²x⁻³⁶ = x⁻⁴⁸
b) y⁻¹⁸y⁻¹⁸= y⁻³⁶
c) z⁻⁶
3.- Write the fraction

Answer:
x=8
Step-by-step explanation:
Area is equal to
A = l * w
50 = ( x+2) ( x-3)
FOIL
50 = x^2 -3x+2x -6
Combine like terms
50 = x^2 -x -6
Subtract 50 from each side
0 = x^2 -x -56
Factor
What two numbers multiply to -56 and add to -1
-8*7 = -56
-8+7 = -1
0 = ( x-8) ( x+7)
Using the zero product property
x-8 =0 x+7 =0
x = 8 x=-7
Since the length cannot be negative x cannot be negative
x=8
I think 80 I’m not sure ........