Hope you could understand.
If you have any query, feel free to ask.
10-5y=1x
-10 -10
-5y= 1x -10
/-5 /-5
y= -1/5x +2
Given:
Consider the height of the rocket, in feet after x seconds of launch is

To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,

It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is
, then the vertex is

Here,
.
So,



So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.
00 x 0.24 = a x 0.40 + ( 700 -a ) x 0.15 = 0.40 a - 0.15 a + 105.00
<span>168.00 = 0.25a + 105.00 </span>
<span>a = 252 </span>
<span>Solution with 40% ....................252 liters........................ans </span>
<span>Solution with 15 % ...................700 - 252= 448 liters.........................ans</span>