Answer:
175%
Step-by-step explanation:
Answer:
is this from a textbok
Step-by-step explanation:
Answer:
See explanation.
Step-by-step explanation:
13 / 13 = 1.
14 - 16 = -2
-2 * 10 = -20
-20 + 12 = -8
-8 - 1 = -9
Answer = -9
Hey there,
It would be devising a plan
Hope this helps :))
<em>~Top♥</em>
Answer:
Angle bisector
Step-by-step explanation:
Find the measure of the angle COA. By angle addition postulate,

From the diagram,

then

Find the measure of the angle BOA. By angle addition postulate,

From the diagram,

then

Find the measure of the angle COB. By angle addition postulate,

From the diagram,

then

This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA