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lilavasa [31]
3 years ago
9

Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card. What is the probability that

he pulls out a 3 first and then pulls out a 2 without replacing them?
a. 1/64
b. 1/56
c. 3/32
d. 3/28
Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

Therefore, the probability is P=3/32.

Step-by-step explanation:

We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.  

We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.

The probability that he pulls out a 3 first is 3/8.

The probability of a second card being 2 is 2/8.

We get:

P=\frac{3}{8}\cdot \frac{2}{8}\\\\P=\frac{6}{64}\\\\P=\frac{3}{32}

Therefore, the probability is P=3/32.

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If each car has the same mass which car will require the longest time to come to a full stop
rosijanka [135]

Answer:

Car D

Step-by-step explanation:

Since the mass is the same, we need to depend on the speed. The lower the speed, the easier/faster to stop. The higher the speed, the longer it will take to come to a stop

5 0
3 years ago
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
kati45 [8]

Question:

Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?

Answer:

1/72

Step-by-step explanation:

<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is  1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is  1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>


<em>I had this same question on my test!</em>


<em>Hope this helped! Good Luck! ~LILZ</em>


3 0
3 years ago
Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer
denis-greek [22]

Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.


Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave.  You get $16.40.  Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

3 0
3 years ago
What is the quotient of m and 7
finlep [7]

Answer:

m/7

Step-by-step explanation:

because m divided by seven is m/7 so that is the answer

4 0
3 years ago
Read 2 more answers
What value of m makes the system of linear equations mx − y + 3 = 0, (2m − 1)x − y + 4 = 0 have no solution?
Morgarella [4.7K]

Answer:

m ≠1  ( all m in R  except 1 )

Step-by-step explanation:

hello :

mx − y + 3 = 0.....(*)

(2m − 1)x − y + 4 = 0 ....(**)

multiply (*) by : -1       you have :   -mx+y-3=0   ....(***)

                                                    (2m − 1)x − y + 4 = 0 ....(**)

add(***) and(**)  : -mx+ (2m − 1)x+1 =0

(2m-m-1)x+1=0

(m-1)x = -1

this system have no solution  if : m-1≠0   means : m ≠1

6 0
3 years ago
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