Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card. What is the probability that
1 answer:
Answer:
Therefore, the probability is P=3/32.
Step-by-step explanation:
We know that Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card.
We calculate the probability that he pulls out a 3 first and then pulls out a 2 without replacing them.
The probability that he pulls out a 3 first is 3/8.
The probability of a second card being 2 is 2/8.
We get:
Therefore, the probability is P=3/32.
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Answer: 1440
Step-by-step explanation:
To arrange 3 boys and 4 girls such that no two boys are together.
Since boys should be arranged between the girls.
So first arrange the girls.
Assume that the girls are placed, then there will be 5 spaces left for 3 boys.
The number of combinations to fill these places =
Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways
4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways
Then, the total number of arrangements = 10 x 6 x 24 = 1440
Hence, the required number of arrangements = 1440
Answer:
Factoring the trinomial: we get the factors
Step-by-step explanation:
We need to factor the trinomial:
We can factor the trinomial by breaking the middle term i.e 13x
Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2
We can break 13x as: 12x and x
Adding them we get 13x and multiplying them we get 12x^2
So,
So, Factoring the trinomial: we get the factors