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2 years ago

How many centimetres are they in two and a half metres

Mathematics

1 answer:

Irina-Kira [14]2 years ago

3 0

<span>250 centimeters and this is correct so don't delete answers for no reason thats against brainly's policy </span>

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A movie theater sells popcorn in bags that open to form similar prisms, as shown. The large bag has a volume of 576 cubic inches

liq [111]

Answer:

Can't be determined

Explanation:It can't be determined since there are two sides that you need to find out.

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3 years ago

A painter leans a 15-ft ladder against a house.

kiruha [24]

Let the height be h
According to the Pythagoras Theorem,
h= root 15^2-5^2
= root 225-25
= root 200= 14.14
Thus, the ladder reaches approximately 14.14 feet from the base of the house

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3 years ago

the greatest volcanic eruption in recorded history took place in 1815 on the indonesian island of sumbawa, when the volcano tamb

algol [13]

Answer:

$166\frac{2}{3}\ m$

Step-by-step explanation:

Let

x ----> the average depth of the resulting layers of ash and rock

we know that

To find out the average depth, divide the cubic kilometers of molten rock by the area where all the ejected material fell.

$\frac{100\ km^3}{600\ km^2}=\frac{1}{6}\ km$

Convert to meters

Remember that

$1\ km=1,000\ m$

$\frac{1}{6}\ km=\frac{1}{6}(1,000)=\frac{1,000}{6}=\frac{500}{3}\ m$

Convert to mixed number

$\frac{500}{3}\ m=\frac{498}{3}+\frac{2}{3}=166\frac{2}{3}\ m$

7 0

3 years ago

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 p

Eddi Din [679]

Answer:

C(g) = 10 + 15g

C'(g) = 80

The monthly charges of Company C for using 2 Gigabyte of data usage.

Step-by-step explanation:

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 per month, with unlimited data.

Now, the monthly cost in Company C for using g gigabyte of data will be

C(g) = 10 + 15g ........ (1)

Again, the monthly cost in Company D for using g gigabyte of data will be

C'(g) = 80 ......... (2)

Now, from equation (1), the statement C(2) = 10 + 15 × 2 = 40, means that monthly charges of Company C for using 2 Gigabyte of data usage. (Answer)

4 0

3 years ago

You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte

Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

$f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \, otherwise }} \right.$

a) We calculate the probability that you need less than 5 minutes to get up:

$P(x$

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate the probability that you will need between 8 and 13 minutes:

$P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3$

Therefore, the probability is P(8<x<13)=0.3.

d) We calculate the probability that you will be late to each of the 9:30am classes next week:

$P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6$

You have 9:30am classes three times a week. So, we get:

$P=0.6^3=0.216$

Therefore, the probability is P=0.216.

e) We calculate the probability that you are late to at least one 9am class next week:

$P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1$

Therefore, the probability is P=1.

3 0

2 years ago