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enot [183]
3 years ago
5

An expansion is a phase in the economic cycle that is characterized by

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

Answer:

 An expansion is characterized by increasing employment, economic growth, and upward pressure on prices.

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Ace Truck leases its 10-ft box truck at $20/day and $0.50/mi, whereas Acme Truck leases a similar truck at $15/day and $0.55/mi.
Masja [62]

Answer:

a) f(x) = 0.5 \frac{dollars}{day} x + 20

g(x) = 0.55 \frac{dollars}{mi} x + 15

b) f(70)=0.5*70 +20 =55

g(70)= 0.55*70 + 15 =53.5

If we want to minimize the cost then we should rent the Acme Truck company.

Step-by-step explanation:

Assuming the following questions.

(a) Find the daily cost of leasing from each company as a function of the number of miles driven and sketch the graph of these functions.

For the Ace truck we know that leases its 10-ft box truck at $20/day and $0.50/mi. So then f(x) representing the daily cost is given by:

f(x) = 0.5 \frac{dollars}{day} x + 20

Where x represent the  number of miles driven

For the Acme Truck we know that leases a similar truck at $15/day and $0.55/mi, so then the g*x( representing daily cost would be given by:

g(x) = 0.55 \frac{dollars}{mi} x + 15

Where x represent the miles driven.

We can see the plot on the figure attached.

(b) Which company should you rent a truck from for 1 day if you plan to drive 70 miles and wish to minimize cost?

If we replace the value x=70 for both functions we got:

f(70)=0.5*70 +20 =55

g(70)= 0.55*70 + 15 =53.5

If we want to minimize the cost then we should rent the Acme Truck company.

7 0
3 years ago
How do u solve this5/6×3​
ELEN [110]

Answer:

5/2

Step-by-step explanation:

5/6 * 3

Reduce the numbers with the greatest common divisor which is 3 since it goes in to both 6 and 3

6/3=2

5/2

4 0
4 years ago
The population of a heard of cattle numbered was 5000 to begin with and was 10,000 after 10 years. If the population was growing
Lapatulllka [165]

Answer:

r=0.0718. The closest value from your given choices is C)r=0.69

Step-by-step explanation:

To solve this we are using the standard exponential growth equation:

f(t)=A(1+r)^t

where

f(t) is the final population after t years

A is the initial population

r is the growth rate in decimal form

t is the time in years

We know from our problem that the initial population is 5000, the final population is 10000, and the time is 10 years, so A=5000, f(t)=10000, and t=10.

Let's replace the values and solve for r:

f(t)=A(1+r)^t

10000=5000(1+r)^{10}

Divide both sides by 5000

\frac{10000}{5000} =(1+r)^{10}

2=(1+r)^{10}

Take root of 10 to both sides

\sqrt[10]{2} =\sqrt[10]{(1+r)^{10}}

\sqrt[10]{2} =1+r

Subtract 1 from both sides

\sqrt[10]{2}-1=r

r=\sqrt[10]{2}-1

r=1.0718-1

r=0.0718

We can conclude that the growth rate of our exponential equation is r=0.0718. The closest value from your given choices is C)r=0.69

3 0
4 years ago
It takes Karl 6 hours to drive 372 miles. If he drives at a constant speed during the 6 hours, what is his unit rate? At this ra
skelet666 [1.2K]
Use the equation speed equals distance over time.
s=372/6
  =62mi/hr

Use the equation distance equals speed times time.
d=62*8
 =496mi in 8 hours
6 0
3 years ago
Help. Fully explain plz
frozen [14]
110/55 is what u get if u add them all up
7 0
3 years ago
Read 2 more answers
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