First, make the table so you can sketch the graph:
x | y
5 | 20
4 | 9 x² - 5 ; x > 3
<u> 3 | </u><u>4 </u><u> </u><u><em>(open dot) </em></u><em> ⇒ </em>from the right
<u> 3 | </u><u>5</u><u> 5 ; x = 3 </u> ⇒ at x = 3
3 | 2 <em>(open dot) ⇒ </em>from the left
2 | 4 -2x + 8 ; x < 3
<u> 1 | 6 </u>
Next, look at the graph (or table) to find the limits:
lim 3⁺ = 4 <em>as x approaches 3 from the right, y approaches 4</em>
lim 3⁻ = 2 <em>as x approaches 3 from the left, y approaches 2</em>
lim 3 = DNE <em>lim 3⁺ ≠ lim 3⁻ so the limit does not exist</em>
f(3) = 5 <em>when x = 3, y = 5</em>
f(x) is NOT continuous at x = 3 <em>because lim 3 ≠ f(3)</em>
Purple and white make up less than 30 %
A horizontal line would be parallel to the x-axis. This means that it would be in the form y= ____. Because coordinates of a point are written as (x,y) the corresponding y coordinate for this horizontal line would be 4.
The final answer is C. y=4
½d + 3/8 = -2d
<span>-½d -½d</span>
<span>3/8 = -2 ½d</span>
<span>/(-2
½) /(-2 ½)</span>
<span>3/20 = d </span>
Answer: To be able to create two intersecting arcs above and below the line segment
Step-by-step explanation:
That is one of the steps to bisecting a line segment lol
