Two-thirds of a number is 22. what is the number?

Write an equation where the variable is divided by a number, and a solution is -4/5

MrMuchimi

Answer:

x/-5

Step-by-step explanation:

Just divide by 5 and the denominator will be 5 meaning x would have to be 4.

Make sure your 5 is negative so the whole equation also ends up negative. x/-5=-4/5

8 0

2 years ago

Whiskers the cat weighs 2 2/3 kg. Piglo weighs 4kg. For each question , write a myipulcation and a division equation, decide whe

Liula [17]

Answer:

1) x= 3/2= 1 1/2

2) x= 2/3

Step-by-step explanation:

1)How many times as heavy as Whiskers is Piglio?

a) Write a multiplication equation for the question.

2 2/3 kg * [x]= 4kg

b) Write a division equation for the question.

4/ 2 (2/3) = x

c) Is the answer greater than 1 or less than 1?

Ans) Greater than 1

d) Find the answer

4/ 8/3= x

x= 3/2= 1 1/2

Pigilo is 1 1/2 times as heavy as whiskers

2)How many times as heavy as Piglio is Whiskers?

a) Write a multiplication equation for the question.

4 kg * [x]= 2 2/3 kg

b) Write a division equation for the question.

2 (2/3)/4 = x

c) Is the answer greater than 1 or less than 1?

Ans) Less than 1

d) Find the answer

8/3/4= x

8/3 * 1/4= x

2/3= x

Whiskers is 2/3 times as heavy as Pigilo.

5 0

2 years ago

Weather reporter reads 0.103 for amount of snowfall. How would he say this?

Romashka [77]

The weather reporter would pronounce 0.103 as 103 thousandths.

4 0

3 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

Steve Ballmer, the current CEO of Microsoft, used to be the manager of his college football team. Among his duties, he had to be

lutik1710 [3]

9514 1404 393

Answer:

a. x + 4y = 160

b. 160

c. 40

Step-by-step explanation:

a. We can define the variables as ...

x = number of 1/2-liter bottles

y = number of 2-liter bottles

For the total number of liters to be 80, we require

1/2x + 2y = 80

We can multiply this by 2 to eliminate the fraction.

x + 4y = 160

__

b. The x-intercept is 160. It is the number of 1/2-liter bottles required when no 2-liter bottles are used.

__

c. The y-intercept is 40. It is the number of 2-liter bottles required when no 1/2-liter bottles are used.

7 0

3 years ago