Two-thirds of a number is 22. what is the number?

4. Between which two whole numbers does V150 lie?

KonstantinChe [14]

Answer:

12 & 13

Step-by-step explanation:

trust me

3 0

3 years ago

A jar contains 3 pennies, 5 nickels, 4 dimes, and 6 quarters. of a coin is selected at random, what is the probability of select

Artemon [7]

Hey there! :)

There are 3 pennies
There is a total of 18 coins; 3 + 5 + 4 + 6 = 18

3 ÷ 18 = 0.16666666667 = 0.17

Your answer is 1/6 or 0.17

Hope this helps :)

3 0

3 years ago

Write an equation for a line parallel to y=-3x-5 and passing through the point (4,-16)

const2013 [10]

Answer:

Insert the numbers into the equation y=3x-5.

the rule states that in every equation the first number is x.so it will be -6=3(4)-5

-6=12-5

-6=7.

If u want, you can leave your answer like that

3 0

2 years ago

Which one is greater??

Andrew [12]

224.9>224.92 hope it helps

8 0

2 years ago

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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