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DaniilM [7]
2 years ago
5

Tweaking existing technology in a new way is usually called _____. leveraged creativity state-of-the-art breakthrough applicatio

ns engineering product adaptation
Computers and Technology
1 answer:
just olya [345]2 years ago
8 0

Answer: Leveraged creativity

Explanation:

Improving functionality and performance of any technology through new and unique methods so that it can lift above the competing organization and technologies. Experts and guides try innovating the technology through various attempts which is caused by maximizing advantage through creativity.

  • Other options are incorrect because application engineering, adaptation of product and state of art breakthrough does not influence the technology  to rise above the competing companies.
  • Thus, the correct option is leveraged creativity
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See explaination

Explanation:

import java.util.*;

import java.lang.Math;

public class Main

{

public static double getRandomDoubleBetweenRange (double min, double max)

{

double x = (Math.random () * ((max - min) + 1)) + min;

return x;

}

public static void main (String[]args)

{

int option, number_of_problems, correct_answer;

double max_operand, average =

0, user_answer, sum, first_number, second_number, multiply,

sum_or_multiply;

Scanner user_input = new Scanner (System.in);

do

{

System.out.println

("Choose the type of problem: \n1. Addition \n2. Multiplication \n3. Mixed \n4. Quit");

option = user_input.nextInt ();

switch (option)

{

case 1:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

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max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

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System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum = first_number + second_number;

if (sum == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

sum);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 2:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 0; i < number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

System.out.println (first_number + " * " + second_number +

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user_answer = user_input.nextDouble ();

multiply = first_number * second_number;

if (multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.out.println ("Incorrect, The Correct answer is " +

multiply);

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

" out of " + number_of_problems +

" correctly. Your average was " + average);

break;

case 3:

correct_answer = 0;

System.out.println ("How many problems?");

number_of_problems = user_input.nextInt ();

System.out.println ("Largest operand?");

max_operand = user_input.nextDouble ();

for (int i = 1; i <= number_of_problems; i++)

{

first_number = getRandomDoubleBetweenRange (0, max_operand);

second_number = getRandomDoubleBetweenRange (0, max_operand);

if (i % 2 == 1)

{

System.out.println (first_number + " + " + second_number +

" = ?");

user_answer = user_input.nextDouble ();

sum_or_multiply = first_number + second_number;

if (sum_or_multiply == user_answer)

{

System.out.println ("Correct!");

correct_answer = correct_answer + 1;

}

else

{

System.

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}

}

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{

System.out.println (first_number + " * " + second_number +

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user_answer = user_input.nextDouble ();

sum_or_multiply = first_number * second_number;

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{

System.

out.println ("Incorrect, The Correct answer is " +

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}

}

}

average = correct_answer * 100 / number_of_problems;

System.out.println ("You answered " + correct_answer +

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case 4:

System.out.println ("Thanks for playing.");

break;

default:

System.out.println ("Please choose a valid option");

break;

}

}

while (option != 4);

}

}

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