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11Alexandr11 [23.1K]
3 years ago
6

The 6 steps for PowerPoint competency from the TED talk in the module "How to Avoid Death by PowerPoint."?

Computers and Technology
1 answer:
KIM [24]3 years ago
6 0

Answer:

1. Do some presentation preparation work

2. Set the right tone and end on a high note.

3. Create sleek and stylish slides.

4. Get your audience to focus.

5. Its all about you.

Explanation:

1. Do some presentation preparation work:

A good presentation begins, not with slides, but with a pencil and paper. Research your audience’s background, interests and capabilities. What do they already know, for instance, and what can they learn from you?

2. Set the right tone and end on a high note:

You have no more than 30 seconds to secure your audience’s attention. So, what attention-grabbing opener will you use?

Visual communications expert Curtis Newbold suggests “a fascinating quote; an alarming or surprising statistic; asking your audience a question; telling a relevant and funny joke… an imaginary scenario; or a demonstration''.

3. Create sleek and stylish slides:

Once you have your story down, you can start to design your slides.  

Before you do, it’s important to think about the practicalities. Will they, for instance, be displayed Widescreen with a 16:9 ratio? Or Standard with 4:3? This might seem like a small detail, but it can make a huge difference in terms of visual impact.

4.  Get your audience to focus:

The most important thing is to grab your audience’s attention straight away – and then maintain it! You want your audience to go away having learned something. So, make it as easy as possible for people to grasp your message “from the off”!

5.  Its all about you:

Finally, remember that, ultimately, it’s you that the audience should be paying attention to, not your slides!

PowerPoint can be used to create great visual aids, but the success of your presentation is determined by the way you deliver them. So, tell your story with a confident, compelling physical presence, and master it by rehearsing it 10 to 15 times.

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Create an instance of your queue that accepts java.lang.String Objects. Starting with an empty queue, use the enqueue(E e) metho
Aleksandr-060686 [28]

Answer:

Code is given below:

Explanation:

ode.java:

public class Node

{

String data;

Node next;

Node prev;

public Node(String data,Node next, Node prev){

this.next=next;

this.data=data;

this.prev=prev;

}

public Node(){

}

public String getData(){

return data;

}

public void setData(String data){

this.data=data;

}

public Node getNext(){

return next;

}

public void setNext(Node next){

this.next=next;

}

public Node getPrev(){

return prev;

}

public void setPrev(Node prev){

this.prev=prev;

}

}

Linked Queue.java:

public class LinkedQueues {

    Node head ;

   Node tail;

int size=0;

public Oueues(){

   this.head=null;

   this.tail=null;

}

public boolean isEmpty()

{

   return head == tail;

}    

 public int getSize()

    {

          return size;

  }    

 public void insert(String data){

   Node tmp = new Node(data,null,null);

    tmp.data=data;

    tmp.next=null;

    if(head==null){

        head=tail=tmp;

        head.prev=null;

    }

    else{

        tail.next=tmp;

        tmp.prev=tail;

        tail=tmp;

 }    

 }

 public String remove(){

  if(head.next==tail)

      return null;// list empty

  Node tmp=head.next;

  head.next=tmp.next;

  tmp.next.prev=head;

  list();

  return tmp.data;

 }

 public void list(){

     System.out.println("Queues");

     if(size==0){

         System.out.println("İs Empty");

     }

    Node tmp=head;

    while(tmp !=tail.getNext()){

        System.out.println(tmp.getVeri()+" ");

      tmp= tmp.getNext();

    }

     System.out.println();

 }

Linkedstack.java:

public class LinkedStack {

Node head = null;

Node tail = null;

int size=0;

     public int getSize() {

    return size;

      }

  public boolean isEmpty()

      {

   return head == null;

   }    

 public void Push(String data) {

    tail = head;

   head = new Node(data,null,null);

   head.data=data;

   head.next= tail;

   head.prev = null;

   if(tail != null) {

       tail.prev=head;

   }

   size++;

 }

 public void Pop() {

   if (!isEmpty()) {

       head = head.next;   // delete first node

       size--;

   } else {

       System.out.println("İs Empty");

   }

}

  public void Top() {

   Node tmp = head;

   while (tmp != null) {

       System.out.println(tmp.getData());

       tmp = tmp.getNext();

   }

}

 }

ArrayBasedQueue.java

import java.util.LinkedList;

import java.util.Queue;

 

public class ArrayBasedQueue

{

 public static void main(String[] args)

 {

   Queue<Integer> q = new LinkedList<>();

 

   // Adds elements {0, 1, 2, 3, 4} to queue

   for (int i=0; i<5; i++)

    q.add(i);

 

   // Display contents of the queue.

   System.out.println("Elements of queue-"+q);

   int removedele = q.remove();

   System.out.println("removed element-" + removedele);

 

   System.out.println(q);

   int head = q.peek();

   System.out.println("head of queue-" + head);

 

   int size = q.size();

   System.out.println("Size of queue-" + size);

 }

}

ArrayBasedStack.java:

import java.io.*;

import java.util.*;

 

public class ArrayBasedStack

{

static void stack_push(Stack<Integer> stack)

{

for(int i = 0; i < 5; i++)

{

stack.push(i);

}

}

 

// Popping element from the top of the stack

static void stack_pop(Stack<Integer> stack)

{

System.out.println("Pop :");

 

for(int i = 0; i < 5; i++)

{

Integer y = (Integer) stack.pop();

System.out.println(y);

}

}

 }

TestTimes.java:

public class TestTimes implements TestTimesInterface

{

 public static enum TimeUnits {};

 public static enum MemoryUnits{};

}

Driver.java:

public class driver

{

public static void main(String args[])

{

   Scanner s = new Scanner(System.in);

   LinkedStack y = new LinkedStack();

   LinkedQueues k = new LinkedQueues();

   ArrayBasedStack as=new ArrayBasedStack();

     ArrayBasedQueue as=new ArrayBasedQueue();

   FileWriter fwy;

   FileWriter fwk;

   File stack = new File("stack.txt");

   if (!stack.exists()) {

       stack.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader reader = null;

   reader = new BufferedReader(new FileReader(stack));

   String line = reader.readLine();

   while (line != null) {

       y.Push(line = reader.readLine());

       System.out.println(line);

   }

   File queue = new File("queue.txt");

   if (!queue.exists()) {

       queue.createNewFile();

   } else {

       System.out.println("already exists ");

   }

   BufferedReader read = null;

   read = new BufferedReader(new FileReader(queue));

   String lines = read.readLine();

   while (lines != null) {

       lines = read.readLine();

       k.insert(lines);

       System.out.println(lines);

   }

int choice;

     System.out.println("1. Stack out- queue add");

     System.out.println("2. Stack add- queue out");

     System.out.println("3. Stack and queue ");

     System.out.println("4. File writer");

     choice = s.nextInt();

   switch (choice) {

       case 1:

           k.insert(s.next());

           k.list();

           y.pop();

           break;

       case 2:

         y.Push(s.next());

           y.Top();

         k.remove();

           break;

       case 3:

           y.Top();

           k.list();

           break;

       case 4:

           fwy = new FileWriter(stack);

           Node no = y.head;

           while (no.next != null) {

               fwy.write("\n" + no.data);

               no = no.next;

           }

           fwy.flush();

           fwy.close();

           fwk = new FileWriter(queue);

           Node noo = k.head;

           while (noo.next != null) {

               fwk.write("\n" + noo.data);

               noo = noo.next;

           }

           fwk.flush();

           fwk.close();

           break;

        }

 

}

}

6 0
3 years ago
Processors for most mobile devices run at a slower speed than a processor in a desktop PC.
kramer

Answer:

True....................

5 0
3 years ago
Read 2 more answers
In a Windows environment, __________ is a powerful tool that enables security administrators to share user and group definitions
spayn [35]

Answer:

Active Directory

Explanation:

Active Directory (AD) is a Microsoft product that consists of several services that run on Windows Server to manage permissions and access to networked resources.

Active Directory categorizes objects by name and attributes. For example, the name of a user might include the name string, along with information associated with the user, such as passwords and Secure Shell (SSH) keys.

7 0
3 years ago
Javier develops sophisticated fashion websites. He has been asked by the owner of a leading fashion brand to create web content
saul85 [17]

Answer:

hyperlinks

Explanation:

Javier should use hyperlinks to show the users the possible choices for their clothing.  This is really a terrible question and not likely in any real world scenario.  Fashion is always forward thinking and on the cutting edge.  When was the last time you went to a fashion website and were left with only choices to click on a hyperlink?  As Tim Gun would say "Make it work."  If I were able I would include a hyperlink using the previous sentence as the clickable link with a URL reference to

https : //en.wikipedia.org/wiki/Tim_Gunn (spaces after https to make this link not get censored)

to illustrate the way to show that hyperlinks have no real application on modern fashion website.  But they would have great utility here inside the answers section.  But they also are cause for a securtity concern and may be killed by the moderators

7 0
3 years ago
This is a graded practice activity. This is not an actual quiz.
Lerok [7]

Answer:

0

Explanation:

x=27

y=5

22+(27-5)

22+(22)

0

8 0
1 year ago
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