Answer:
(x, y) = (40, 30)
Step-by-step explanation:
A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.
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An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:
y = 110 -2x . . . . . . subtract 2x from both sides
Using this in the first equation gives ...
3x -4(110 -2x) = 0 . . . . substitute for y
11x = 440 . . . . . . . . . simplify, add 440
x = 40 . . . . . . . . . . divide by 11
y = 110 -2(40) = 30
The solution is (x, y) = (40, 30).
Let x, y and z denote the weighs of car X, car Y and car Z, respectively.
We know that car X weighs 136 more than car Z, this can be express by the equation:
We also know that Y weighs 117 pounds more than car Z, this can be express as:
Finally, we know that the total weight of all the cars is 9439, then we have:
Hence, we have the system of the equations:
To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:
Now that we have the value of z we plug it in the first two equations to find x and y:
Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.
Answer:
697.05$
Step-by-step explanation:
Mark as brainliest
Answer:
168
X + 126
i
X
Step-by-step explanation:
Apply the distributive property:
7
i
X ⋅ (
3
i ⋅ −
8 + 3
i
(
−
6
i
)
)
Multiply
−
8 by 3
Multiply
3
i
(
−
6
i
)
Simplify each term
Apply the distributive property
Multiply
7
i
X (
−
24
i
)
Multiply
18 by 7
Simplify each term.
