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arsen [322]
3 years ago
8

Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.

Mathematics
1 answer:
Alika [10]3 years ago
7 0

Answer:

No.

Step-by-step explanation:

No, because you can multiply or divide the length and breadth of rectangle A by the same number to get B

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If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,<br> find f(x) – g(x).<br><br> Answer: x^2 - 4x + 3
Nadusha1986 [10]

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

  Combine like terms

f(x) – g(x) = x^2 - 4x + 3

 

5 0
3 years ago
Help will give brainliest!!!!!!
sashaice [31]

Answer:

2.5

type A/B

Step-by-step explanation:

10/2.5=4

15/6=2.5

18/7.2=2.5

7 0
3 years ago
Label the quadrants IV​
nevsk [136]

Answer:

Quadrant IV is always in the bottom right corner.

8 0
2 years ago
If a starting number is 30 and it falls to 11 what % decrease is that?
jonny [76]

Answer:

The question would've given you to what number you should round up your answer.

Answer is:

Whole number:

63%

1 decimal place:

63.3%

2 decimal places:

63.33%

Exact number:

\frac{190}{3}%

Step-by-step explanation:

So the starting no. = 30

Ending no. = 11

In order to evaluate the percentage of decrease we:

(Ending number/starting number) * 100

So:

\frac{11}{30} *100 = \frac{11}{3} *10 = \frac{110}{3}%%

To find the Decrease percentage:

100 % - 110/3 %

= 63.333%

3 0
3 years ago
Help me answer this question the picture is linked below. I will be reporting spam answers/one's with no effort put in.
Brums [2.3K]

Answer:

I think this is right? The instructions seem a bit vague to me...

Condition A: Many

Condition B: One

Condition C: One

Condition D: Many

Condition E: Many

Condition F: One

Step-by-step explanation:

So Condition A: A rectangle with 4 right angles is going to be in many quadrilaterals because squares are also a rectangle with 4 right angles. So condition A has 2 or maybe more that I forgot about.

Condition B: A square with one side measuring 5 inches is one quadrilateral. Squares are one specific type of quadrilateral so they're probably going to go into one quadrilateral

Condition C: A rhombus can sometimes also be a square, but since in this case, it's angle is only 43°, it should be one quadrilateral.

Condition D: There are a lot of parallelograms. Just because one angle is 32°, it doesn't mean there is just one. There are rhombuses and trapezoids that have 32° angles that would be parallelograms. This one is many.

Condition E: This one was hard for me to visualize, but I'm pretty sure this one is also many. There are at least 2. One side could be 6 inches and another could be 8 inches and then, it could be vice versa, so there are probably more than one. This one is many.

Condition F: Is this even possible? I think it's one.

6 0
3 years ago
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