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Lady bird [3.3K]
4 years ago
12

Am I right or wrong? Please explain or show your work to solve this problem. Thanks!

Mathematics
1 answer:
Shkiper50 [21]4 years ago
5 0

Answer:

  Your choice is correct

Step-by-step explanation:

My favorite on-line calculator shows the same result.

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3 years ago
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Answer:

\large\boxed{y=\dfrac{32}{9}}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}x+3y=1\\2x-3y=-30\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad3x=-29\qquad\text{divide both sides by 3}\\.\qquad x=-\dfrac{29}{3}\\\\\text{put the value of x to the first equation}\\\\-\dfrac{29}{3}+3y=1\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\left(-\dfrac{29}{3\!\!\!\!\diagup_1}\right)+(3)(3y)=(3)(1)\\\\-29+9y=3\qquad\text{add 29 to both sides}\\\\9y=32\qquad\text{divide both sides by 9}\\\\y=\dfrac{32}{9}

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3 years ago
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