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jasenka [17]
3 years ago
5

Find the exact length of the third side.

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

 

\displaystyle\bf\\\textbf{A third side is hypotenuse.}\\\\The~length~of~the~hypotenuse=\sqrt{cat1^2+cat2^2}~~~(T.Pithagoras)\\\\The~length~of~the~hypotenuse=\sqrt{4^2+5^2}=\sqrt{16+25}=\boxed{\bf\sqrt{41}}

 

Savatey [412]3 years ago
5 0

Answer:

√41 or 6.40

Step-by-step explanation:

Pythagorean theorem:

a² + b² = c²

The third side is considered the hypotenuse (c²).

a² and b² will be represented by the legs.

a² = 4²

b² = 5²

c² = c²

4² + 5² = c²

16 + 25 = c²

31 = c²

√41 = c

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William works for a video game store. He has 30 video games at the start of the day. He sold 6 video games per day. Write the ru
Simora [160]

Answer:

See below.

Step-by-step explanation:

It isn't clear if the problem wants to know the number of video games sold, or the number remaining.

<h2><u>Remaining Games</u></h2>

Let N be the number of video games in the store after d days.  Assume none are replaced after they are sold.

N = 30 - 6d [Remaining games, N, are 30 minus the number of days, d, times 6 games/day]  We need to also state 30 ≥ N ≥ 0.  [No negative games are allowed.  They are bad for morale].

<h2><u>SOLD Games</u></h2>

Let N be the number of games sold over n days.

N =  6d   [Games sold]  Here, we need to state 0 ≤ N ≤ 30.  [We can't sell more games than we have, unless you are a fast runner].

8 0
2 years ago
A movie theater sells morning tickets (m) for $4 and regular tickets (e) for $6. During one week, the theater earned $6000. The
grin007 [14]

Answer:

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help me please thanks​
Zarrin [17]

FORMULA:

  • Pythagorean property —: h² = b² + p², where h = hypotenuse, b = base, p = perpendicular.

ANSWER:

By pythagorean property,

  • x² = 25² + 100²
  • x² = 625 + 10000
  • x² = 10625
  • x = √10625
  • x = 103 cm rounded.

Hence, the length of x is 103 cm.

8 0
3 years ago
Solve the equation 4(3-2x)=22
jeka94
<span>4(3-2x)=22
4(3) - 4(2x) = 22
12 - 8x = 22
8x = 12 - 22
8x = -10
x = -10/8 = -5/4 
or
x = -1.25</span>
8 0
4 years ago
Which series of transformations shows that pentagon A is congruent to pentagon B?
Fantom [35]
The <u>correct answer</u> is:

B) A 90° counterclockwise rotation about the origin, followed by a reflection across the x-axis, followed by a translation 8 units right and 1 unit up.

Explanation:

The coordinates of the <u>points of the pre-image</u> are:
(3, 1)
(3, 4)
(5, 7)
(6, 5)
(6, 2)

The coordinates of the <u>points of the image</u> are:
(7,-2)
(4,-2)
(1,-4)
(3,-5)
(6,-5)

A 90° counterclockwise rotation about the origin negates the y-coordinate and switches it and the x-coordinate.  Algebraically,
(x,y)→(-y,x).

When this is applied to our points, we get:
(3, 1)→(-1, 3)
(3, 4)→(-4, 3)
(5, 7)→(-7, 5)
(6, 5)→(-5, 6)
(6, 2)→(-2, 6)

A reflection across the x-axis negates the y-coordinate.  Algebraically,
(x, y)→(x, -y).

Applying this to our new points, we have:
(-1, 3)→(-1, -3)
(-4, 3)→(-4, -3)
(-7, 5)→(-7, -5)
(-5, 6)→(-5, -6)
(-2, 6)→(-2, -6)

A translation 8 units right and 1 unit up adds 8 to the x-coordinate and 1 to the y-coordinate.  Algebraically,
(x, y)→(x+8, y+1).

Applying this to our new points, we have:
(-1, -3)→(-1+8,-3+1) = (7, -2)
(-4, -3)→(-4+8,-3+1) = (4, -2)
(-7, -5)→(-7+8,-5+1) = (1, -4)
(-5, -6)→(-5+8,-6+1) = (3, -5)
(-2, -6)→(-2+8,-6+1) = (6, -5)

These match the coordinates of the image, so this is the correct series of transformations.
3 0
4 years ago
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