Can you please help me with this question it is confusing for me.
1 answer:
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Answer:
The altitudes of ΔTSP is SC is 8 unit ,
PA is 5 unit ,
TB is 5 unit .
Step-by-step explanation:
Given as :
The Triangle Δ TSP having side TS , SP , TP
The measure of TS = 12 cm
The measure of SP = 10 cm
The measure of TP = 10 cm
Let The altitude from point T on side PS = TB
The altitude from point S on side PT = SC
The altitude from point P on side TS = PA
The altitude divide the sides
TS = TA + AS
PS = PB + PS
PT = PC + CT
So, From Pythagoras theorem
PA² = PS² - AS²
PA² = 10² - 5²
Or, PA² = 100 - 25
Or, PA =
∴ PA = 5 unit
Again
TB² = TS² - BS²
TB² = 10² - 5²
Or, TB² = 100 - 25
Or, TB =
∴ TB = 5 unit
Similarly
SC² = TS² - TC²
SC² = 10² - 6²
Or, SC² = 100 - 36
Or, SC =
∴ SC = 8 unit
Hence The altitudes of ΔTSP is SC is 8 unit , PA is 5 unit , TB is 5
unit . Answer