Answer:
Step-by-step explanation:
so why this kind of problem is so confusing is b/c it's 2 problems in one
if you were to expand this it look like this
10 ≤2x
and
2x ≤x+9
This is really saying.. that x has a range.. and that the 1st equations is the lower stop point, and that the 2nd equations is the upper stop point
once it's taken apart.. I bet you can solve it pretty quickly.
5≤x
and
x ≤9
then just put it back together in that confusing .. yet handy way to write it,
5≤x≤9
Answer:
23 tallys all you need to do (form what i was taught ) is add up all the tallys
b
Answer:
Step-by-step explanation:
It usually works well to let a variable represent quantity of the highest-value contributor. Here, that is the quantity of adult tickets.
Let "a" represent the number of adult tickets sold. Then (324-a) is the number of admission fees for children. The total revenue is ...
5.40a +2.50(324 -a) = 1390
2.90a +810 = 1390 . . . . eliminate parentheses
2.90a = 580 . . . . . . . . . subtract 810
a = 200 . . . . . . . . . . . . . .divide by 2.90
The number of children admitted was 124; the number of adults admitted was 200.
1. 1x-11. 6x+9 + 5x-20 = 1x-11
2. -2x-11. X-8 -3x-3 = -2x-11
6(5x+2+x)=6(6x+2) Second expression
6(5x+2+x)=6(6x+2)=6(6x)+6(2)=36x+12 Third expression
Answer: The two expressions are equivalent to 6(5x+2+x) are:
Second expresion: 6(6x+2) and
Third expression 36x+12
