Answer:
Distance between Montpelier and Columbia is 1020
Step-by-step explanation:
51 mi/hr average:
d = 51 t
60 mi/hr average:
d t = 60*(t-3)
Substitute (1) into (2)
51 t = 60*(t-3)
51 t = 60 t + 180
9 t = 180
t = 20
d = 51 t
= 51 (20)
= 1020
let see distance is 1020 lets check
51 t = 60 * (t-3)
51 (20)= 60* (20-3)
1020 = 60*17
1020 = 1020
3 and 4
Step-by-step explanation:
y=5x
y=5(0)
y=0
y=5x
y=5(10)
y=50
y=5x
y=5(51)
y=255
y=5x
y=5(400)
y=2000
There exists the same question with an attachment where angle 8 and 7 are supplementary and angle 7 and 5 are vertical angles. From this, the equation that we may derive from the given is,
(2x + 15) + (3x) = 180
The value of x is 33. Substitute this value to x of angle 7, 2(33) + 15 = 81. Thus, the measure of angle 5 is also 81 degrees.
Ok so, to get the next term, triple the last one you have and add 2.