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laiz [17]
3 years ago
7

Given the following diagram, enter the required information. m BXA = 30° 20', m CXB = 40° 35'. m CXA __° __'.

Mathematics
2 answers:
klasskru [66]3 years ago
5 0
The picture in the attached figure

we know that

m∠BXA = 30° 20'
m∠CXB = 40° 35'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = 30° 20' + 40° 35'
m∠CXA = 70° 55'

therefore

the answer is
m∠CXA = 70° 55'

Andrews [41]3 years ago
3 0
I saw the diagram.

m∠BXA = 30° 20'
m∠CXB = 40° 35'

m∠CXA = ?

m∠CXA = m∠BXA + m∠CXB
m∠CXA = 30° 20' + 40° 35'
m∠CXA = 70° 55'
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Answer:

a. Probability = 0.97735

b. Probability = 0.92294

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No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

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All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

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Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

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If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

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7 0
3 years ago
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hjlf

Answer:

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3 years ago
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