This is x^3+x^2+1=-x in math terms, where x is the number. So x^3+x^2+x+1=0. We can write this: x^2(x+1)+(x+1)=(x^2+1)(x+1)=0. The only real solution is x+1=0, so x=-1.
Hopefully that makes sense
Step-by-step explanation:
Thus, 1 is the only repeating digit which is repeating infinite number of times.
Answer:
is questions no 6 is the correct answer