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Serhud [2]
3 years ago
5

Given that EFGH is a kite, what is m∠EHG?

Mathematics
2 answers:
yuradex [85]3 years ago
8 0
Assuming angle F is 68°, angle H will be
.. 360° -2*102° -68° = 88° . . . . . . . . selection B
Tju [1.3M]3 years ago
4 0

For a better understanding of the solution given here please find the attached file which has the diagram of the kite EFGH.

As can be seen from the diagram, \angle FEH=\angle FGH=102^{\circ}

Also, it is given that \angle EHG=68^{\circ}

We are required to find the \angle EFG.

To proceed we know that a kite is a quadrilateral and in a quadrilateral the sum of the interior angles is 360 degrees. Thus, we will get:

m\angle FEH+m\angle EHG+m\angle FGH+m\angle EFG=360^{\circ}

Plugging in the given values we get:

102^{\circ}+68^{\circ}+102^{\circ}+m\angle EFG=360^{\circ}

This will give:

m\angle EFG=88^{\circ}

Therefore, Option B is the correct option.

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Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

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4 0
1 year ago
I really need this pls
Schach [20]

Answer:

\displaystyle m=\frac{-2}{3}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Reading a Cartesian plane
  • Coordinates (x, y)
  • Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (3, 1)

Point (0, 3)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute in points [Slope Formula]:                                                            \displaystyle m=\frac{3-1}{0-3}
  2. [Fraction] Subtract:                                                                                         \displaystyle m=\frac{2}{-3}
  3. [Fraction] Rewrite:                                                                                          \displaystyle m=\frac{-2}{3}
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