Question

Given that EFGH is a kite, what is m∠EHG?

Answer 1

Assuming angle F is 68°, angle H will be
.. 360° -2*102° -68° = 88° . . . . . . . . selection B

Answer 2

For a better understanding of the solution given here please find the attached file which has the diagram of the kite EFGH.

As can be seen from the diagram, $\angle FEH=\angle FGH=102^{\circ}$

Also, it is given that $\angle EHG=68^{\circ}$

We are required to find the $\angle EFG$.

To proceed we know that a kite is a quadrilateral and in a quadrilateral the sum of the interior angles is 360 degrees. Thus, we will get:

$m\angle FEH+m\angle EHG+m\angle FGH+m\angle EFG=360^{\circ}$

Plugging in the given values we get:

$102^{\circ}+68^{\circ}+102^{\circ}+m\angle EFG=360^{\circ}$

This will give:

$m\angle EFG=88^{\circ}$

Therefore, Option B is the correct option.