How to solve this equation x=b

a 90% confidence interva is constructed for the population mean. If a 95% confidence interval had been constructed instead (ever

zhuklara [117]

Answer: increased

Step-by-step explanation:

An x% confidence interval indicates that a person can be x% confident that true population parameter lies in it.

More level of confidence more width of the interval.

As level of Confidence interval increases width of interval increases.

Width of interval $\propto$ level of Confidence interval

So, If a 95% confidence interval had been constructed instead of 90% the width of the interval would have been<u> increased.</u>

6 0

3 years ago

Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =

dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0

3 years ago

Can anyone plzzzz help me with this question of linear equation in two varaiable plzzzzzz... Its very important... Plz solve it

kotegsom [21]

That's not a linear system, but you have an awesome school system for giving you this problem.

$\dfrac 5 y - \dfrac 2 x = \dfrac{13}6$

Multiply by 6xy to clear the fractions.

$30x - 12y = 13 xy$

That's a second degree equation, also known as a conic. That one happens to be a hyperbola.

$30x = y(13 x +12)$

$y = \dfrac{30x}{13 x + 12}$

Let's clear the fractions from the second equation, multiplying out common denominator xy:

$\dfrac {36} x - \dfrac {24} y = 1$

$36y - 24 x = xy$

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

$36 \left( \dfrac{30x}{13 x + 12} \right) - 24 x = x \left( \dfrac{30x}{13 x + 12} \right)$

$36(30x) -24 x(13x + 12) = 30x^2$

$1080 x - 312 x^2- 288 x = 30x^2$

$x(792 - 342 x)= 0$

$x = 0 \textrm{ or } x=792/342 = \dfrac{44}{19}$

We have to rule out x=0 because it's in the denominator.

$y = \dfrac{30x}{13 x + 12} = \dfrac{30(44/19)}{13(44/19)+12}$

$y = \dfrac{33}{20}$

Answer: (44/19, 33/20)

8 0

3 years ago

Astrid is looking for a job at a call center. Call center A offers her 15 dollars per hour and call center B offers her 25 cents

KIM [24]

Call center A and B offers equal wages.

<h3>what is Equation?</h3>

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

The formula for wages = P/t

First, P= 15 dollars

= 1500 cents

time= 1 hour= 60 minutes

then, the unit rate is

=1500/60

= 25 cents/ min

Second, P= 25 cents

time= 1 minutes

then, the unit rate is

=25/1

= 25 cents/ min

Hence, Call center A and B offers equal wages.

Learn more about equation here:

brainly.com/question/10413253

#SPJ1

6 0

1 year ago

I need help with this please

sergeinik [125]

46. They are corresponding angles. if you get rid of the line in between 46 and C then youll see that they are on 1 line and corresponding angles are always equal

3 0

3 years ago

How to solve this equation x=b_cd ,for c