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tia_tia [17]
3 years ago
15

Hey can someone please help 15 points

Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

See attachment (red rectangle)

Step-by-step explanation:

Since the upper left is at (-4,4) and upper-right is at (4,4)

The length of the rectangle is

l =  |4 -  - 4|  = 8

Since the perimeter is 20, we have:

20 = 2(8 + w)

10 = 8 + w

w = 2

Therefore we need to draw a rectangle with dimension 8 by 2

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hoa [83]

Ann recipe produces the sandwiches with the most peanut butter flavor

Step-by-step explanation:

The given is:

1. Ann uses 12 1/4 ounces of peanut butter to make 50 1/2 Sandwiches

2. Ben uses 7 1/4 ounces of peanut butter to make 48 1/2

3. Cal uses 15 1/2 ounces of peanut butter to make 85 1/2 sandwiches

To find whose recipe produces the sandwiches with the most peanut

butter flavor we must find the quantity of butter per sandwich in each

recipe

∵ Ann uses 12.25 ounces of peanut butter to make 50.5 Sandwiches

- Divide the quantity of butter by the number of sandwiches

∵ 12.25 ÷ 50.5 = 0.2426 ounce per sandwich

Ann recipe produces the sandwiches with 0.2426 ounce per sandwich

∵ Ben uses 7.25 ounces of peanut butter to make 48.5 Sandwiches

- Divide the quantity of butter by the number of sandwiches

∵ 7.25 ÷ 48.5 = 0.1495 ounce per sandwich

Ben recipe produces the sandwiches with 0.1495 ounce per sandwich

∵ Cal uses 15.5 ounces of peanut butter to make 85.5 Sandwiches

- Divide the quantity of butter by the number of sandwiches

∵ 15.5 ÷ 85.5 = 0.1813 ounce per sandwich

Cal recipe produces the sandwiches with 0.1813 ounce per sandwich

∵ The greatest quantity of butter per sandwich is 0.2426 ounce

∴ Ann recipe produces the sandwiches with the most peanut

  butter flavor

Ann recipe produces the sandwiches with the most peanut butter flavor

Learn more:

You can learn more about the rate in brainly.com/question/317616

#LearnwithBrainly

3 0
3 years ago
If A( 6, -1) , B( 1,3) and C( k, 8) are three points such that AB = BC, find the value of k
Drupady [299]

Answer:

De value of k is 9

Step-by-step explanation:

6,-1

b(1,3)

(k,8)

am using bodmas

a6-1×1=6a

b1×3=3b

abc=8

6a+3b+8=17-8

=9

7 0
2 years ago
A side of the triangle below has been extended to form an exterior angle of 164º. Find the value of x.​
OverLord2011 [107]

Answer:

x=111

Step-by-step explanation:

the supplementary angle is 16. triangles should add up to 180.

4 0
3 years ago
Find all solutions of each equation on the interval 0 ≤ x < 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
2 years ago
Read 2 more answers
Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?
Anit [1.1K]

Answer:

\dfrac{p^{7} q}{160}

Step-by-step explanation:

\dfrac{(4p^-4 q)^-2}{10pq^-3} =

= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}

= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}

= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}

= \dfrac{1}{160}p^{7} q

= \dfrac{p^{7} q}{160}

4 0
2 years ago
Read 2 more answers
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