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svetlana [45]
3 years ago
15

The school band director determined from past experience that if they charge t dollars for a ticket to the concert, they can exp

ect attendance of 1000-50t. The director used this model to figure out that the ticket price needs to be $8 or greater in order for at least 600 to attend. Do you agree with his claim? Why or why not?
Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

You, don't agree with the claim. Valid claim, t ≤$8

Step-by-step explanation:

From experience as mentioned in the question, charging $ t , the expected attendance is 1000-50t.

If price of the ticket is t ≥$8, then attendance will be ≥600.

Checking the validity of this claim, lets assume t=$8 and use it in the equation;

Attendance= 1000-50t

Attendance=1000-50*8

Attendance=1000-400=600

However for t=9, attendance will be 1000-50*9=1000-450=550

This shows that for the number of people attending to be 600 and more, the value of t in dollars should be $8 or less, thus the claim in not valid.

Learn More

Inequalities:brainly.com/question/3453985

Keywords: ticket, concert, attendance,model,claim

#LearnwithBrainly

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The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
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Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

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The exponential probability distribution, with mean m, is described by the following equation:

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The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

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We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

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P(X > x) = 0.08

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e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

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x = -\frac{\ln{0.08}}{0.01}

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