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krok68 [10]
4 years ago
5

How many vertices and edges does a cuboid have

Mathematics
1 answer:
anastassius [24]4 years ago
4 0
A  cuboid has 8 vertices and 12 edges
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During the 2019 Major League Baseball regular season, there were 2,429 games played, and the home team won in 1,286 of these gam
enyata [817]
I don’t know what the answer to the question is
4 0
3 years ago
You sell tickets for a fundraiser. You give half of the tickets to your sister to sell. You sell 25 of your half of the tickets
hodyreva [135]

Answer:

84 tickets

Step-by-step explanation:

So first off lets add the tickets we sold to the tickets we have left. Lets x equal the amount of tickets we started with before selling.

25+17=x

Add them up.

42=x

We started with 42 tickets. To find how many tickets we had before spiting the tickets. We need to multiply our tickets by 2 since we had half. Let y be this number

42*2=y

Multiply them up

84=y

We started with 84 tickets.

8 0
3 years ago
If the mean of 20, y, 10,5,15 is 22 find the value of y​
QveST [7]
Looks like 14.4 because you have to add them all together and divide by the total numbers
(20+22+10+5+15)/ 5
8 0
3 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
A line goes through the point (-3,2) and has a slope of 1. Write the equation of this line in standard form .
asambeis [7]

Answer:

y - 2 = x + 3

y = x + 5

-x + y = 5 standard form

4 0
4 years ago
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