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marshall27 [118]
3 years ago
11

Solve the following system algebraically

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Step-by-step explanation:

I'm going to give you the explanation first.

Let's start by making the equations more manageable.

y=\frac{x}{2} \\2y=x\\

There you are for the first.

Now insert that value into the second:

2x^{2} -y^2=7\\2(2y)^2-y^2=7\\4y^2-y^2=7\\3y^2=7\\y^2=\frac{7}{3} \\y=+or-\sqrt{\frac{7}{3} }

We now have the value for y, and can solve for x.

Can you solve for x on your own?

Feel free to comment with questions. Have a great day!

forsale [732]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

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