Question

Solve the following system algebraically

Answer 1

Step-by-step explanation:

I'm going to give you the explanation first.

Let's start by making the equations more manageable.

$y=\frac{x}{2} \\2y=x$

There you are for the first.

Now insert that value into the second:

$2x^{2} -y^2=7\\2(2y)^2-y^2=7\\4y^2-y^2=7\\3y^2=7\\y^2=\frac{7}{3} \\y=+or-\sqrt{\frac{7}{3} }$

We now have the value for y, and can solve for x.

Can you solve for x on your own?

Feel free to comment with questions. Have a great day!

Answer 2

Answer:

x=3

Step-by-step explanation: