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3 years ago

Solve the following system algebraically

Mathematics

2 answers:

bonufazy [111]3 years ago

8 0

Step-by-step explanation:

I'm going to give you the explanation first.

Let's start by making the equations more manageable.

$y=\frac{x}{2} \\2y=x\\$

There you are for the first.

Now insert that value into the second:

$2x^{2} -y^2=7\\2(2y)^2-y^2=7\\4y^2-y^2=7\\3y^2=7\\y^2=\frac{7}{3} \\y=+or-\sqrt{\frac{7}{3} }$

We now have the value for y, and can solve for x.

Can you solve for x on your own?

Feel free to comment with questions. Have a great day!

forsale [732]3 years ago

3 0

Answer:

x=3

Step-by-step explanation:

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Find the x- and y-intercepts of −x+y=−3. (Enter each intercept in the form (a,b).)

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(1,-2)

(0,-3)

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Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

Equation 1: 8x+2y=308x+2y=30

Tems11 [23]

Answer:

Part a) We should try to eliminate the y's because the coefficients are the same

Part b) The solution is the point (6,-9)

Step-by-step explanation:

Part a) Which variable pair should we try to eliminate?

we have

$8x+2y=30$ ----> equation 1

$7x+2y=24$ ----> equation 2

Solve by elimination

We should try to eliminate the y's because the coefficients are the same

Part b) What is the solution to the system?

Multiply equation 2 by -1 both sides

$-1(7x+2y)=-1(24)$

$-7x-2y=-24$ -----> equation 3

Adds equation 1 and equation 3

$8x+2y=30\\-7x-2y=-24\\-------\\8x-7x=30-24\\x=6$

Find the value of y

$8x+2y=30[/tex[tex]8(6)+2y=30$

$2y=30-48$

$y=-9$

The solution is the point (6,-9)

8 0

3 years ago

Which equation is the inverse of 2(x-2)squared=8(7+y)

dsp73

Answer:

$f^{-1}(x)=2(+/-)2\sqrt{(7+x)}$

Step-by-step explanation:

we have

$2(x-2)^{2}=8(7+y)$

step 1

Exchange x for y and y for x

$2(y-2)^{2}=8(7+x)$

step 2

isolate the variable y

$(y-2)^{2}=4(7+x)$

take the square root both sides

$y-2=(+/-)\sqrt{4(7+x)}$

$y=2(+/-)\sqrt{4(7+x)}$

step 3

Let

$f^{-1}(x)=y$

$f^{-1}(x)=2(+/-)\sqrt{4(7+x)}$

$f^{-1}(x)=2(+/-)2\sqrt{(7+x)}$ ----> equation of the inverse

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3 years ago