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Ann [662]
3 years ago
13

Help me please,show ur work,Thanks

Mathematics
1 answer:
Andrew [12]3 years ago
5 0
$75
15÷20%=$75
So the origanal price was $75
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Find four consecutive multiples of 3 such that the product of the first, third, and fourth is 1080
Dovator [93]

Answer:

<u>Therefore, we have 6, 9, 12, and 15, that are the first, second, third and fourth consecutive multiples of 3, such the product of 6, 12 and 15 is 1,080.</u>

Step-by-step explanation:

Let's find the factors of 1,080, as follows:

1,080 Dividing by 2 (1,080/2)

540 Dividing by 2 (540/2)

270 Dividing by 2 (270/2)

135 Dividing by 3 (135/3)

45 Dividing by 3 (45/3)

15 Dividing by 3 (15/3)

5 Dividing by 5 (5/5)

1

In consequence, we have:

5 * 3 * 3 * 3 * 2 * 2 * 2

Let's find out what multiples of 3 there are:

5 * 3 = 15 is a multiple of 3,

And 3 * 3 * 2 * 2 * 2 is remaining.

3 * 2 = 6 is also a multiple of 3,

And 3 * 2 * 2 is remaining

3 * 2 * 2 = 12 is also a multiple of 3.

<u>Therefore, we have 6, 9, 12, and 15, that are the first, second, third and fourth consecutive multiples of 3, such the product of 6, 12 and 15 is 1,080.</u>

7 0
3 years ago
Which of the following question would use the calulation 7 x 1/8
Damm [24]

Answer: The answer is D: a pizza is cut into 8 slices Beth eats 7 of them. what fraction of the pizza did Beth eat.

Step-by-step explanation:

If there are 8 slices and 7 of them have been eaten, that means 7/8 have been consumed.

5 0
2 years ago
Which quadrilateral’s diagonals do not create a 90° angle at its intersection?
Shtirlitz [24]
A Rhombus and a Kite are the same thing they are the answer
4 0
3 years ago
Read 2 more answers
43 children attended a birthday party were cake burgers and hotdogs were served
bekas [8.4K]

Answer: Each kid will receive one piece of cake and 1 hot dog, so 43 x 2 = 86

Step-by-step explanation:

43x2= 86

7 0
3 years ago
Help me please ASAP
Mashutka [201]

Answer: \frac{5}{35}

Step-by-step explanation:

Since, the total number of contestant = 7,

Thus, the probability that out of 3 contestant, me and my friend is chosen

= \frac{2_C_2\times 5_C_1}{7_C_3}

= \frac{\frac{2!}{2!0!}\times \frac{5!}{1!\times 4!}}{\frac{7!}{4!\times 3!}}

= \frac{1\times 5}{\frac{7\times 6\times 5\times 4!}{4!\times 6}}

=  \frac{5}{35}

⇒ Third Option is correct.

4 0
3 years ago
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