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ratelena [41]
4 years ago
8

(Photo)

Mathematics
2 answers:
Fantom [35]4 years ago
8 0

Answer:  The correct options is (D) 128 units³.

Step-by-step explanation:  We are given to find the volume of the regular pyramid shown in the figure.

The VOLUME of a regular pyramid with base area 'b' square units and height 'h' units is given by

V=\dfrac{1}{3}\times b\times h.

In the given figure, we have

base area = 8 × 8 = 64 units²   and   height, h = 6 units.

Therefore, the volume of the regular pyramid is

V=\dfrac{1}{3}\times b\times 64\times 6=\dfrac{1}{3}\times =128~\textup{units}^3.

Thus, the required volume is 128 units³.

Option (D) is correct.

poizon [28]4 years ago
5 0
First, set up the equation.
V=(l*w*h)/3
Substitute the values for the variables.
V=(8*8*6)/3
Simplify.
V=(384)/3
V=128 cubic units
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7 0
3 years ago
Can you help? this is on my homework?
Alika [10]
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4 years ago
The weight of crackers in a box is stated to be 16 ounces. The amount that the packaging machine puts in the boxes is believed t
krek1111 [17]

Answer:

99.99% probability that the mean weight of a 50-box case of crackers is above 16 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 16.15, \sigma = 0.3, n = 50, s = \frac{0.3}{\sqrt{50}} = 0.0424

What is the probability that the mean weight of a 50-box case of crackers is above 16 ounces?

This is 1 subtracted by the pvalue of Z when X = 16. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16 - 16.15}{0.0424}

Z = -3.54

Z = -3.54 has a pvalue of 0.0001

1 - 0.0001 = 0.9999

99.99% probability that the mean weight of a 50-box case of crackers is above 16 ounces

3 0
3 years ago
Please need help on this
umka2103 [35]
A "solution" is where the graph crosses the
x-axis so while the quadratic has no real solutions, the straight line passing through it does as it intersects the x-axis at x=-2.
Hope this helps! :)
6 0
4 years ago
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