Answer:
Hey There!
Let's solve....
Radius=5cm
Angle = pi/3
Therefore arc length= Radius×angle
The arc length is 5.23 cm when Theta=pi/ 3 and radius is 5 cm.
<h2>I hope it is helpful to you...</h2><h3>Cheers!_________</h3>
NEED HELP WILL GIVE OUT BRAINLIEST AND POINTS
1 answer:
Part 1) <span>Find the area
we know that
the area of the triangle is
A=b*h/2
in this problem
b=9
h=12
so
A=9*12/2-----> A=54 units</span>²
the answer part 1) is
Area=54 units²
Part 2) <span>Find the area of the kite
see the picture attached with letters to better understand the problem
we know that
The area of a Kite is </span><span>half the product of the diagonals
</span><span>
step 1
find CB
applying Pythagoras Theorem
AB</span>²=AC²+BC²------> BC²=AB²-AC²-----> BC²=5²-3²----> BC²=16
<span>BC=4
so
the diagonals are
(10+4) and (3+3)---------> 14 and 6
Area=(1/2)*[14*6]----> Area=42 units</span>²<span>
the answer Part 2) is
the area of a kite is 42 units</span>²
we know that
the area of the triangle is
A=b*h/2
in this problem
b=9
h=12
so
A=9*12/2-----> A=54 units</span>²
the answer part 1) is
Area=54 units²
Part 2) <span>Find the area of the kite
see the picture attached with letters to better understand the problem
we know that
The area of a Kite is </span><span>half the product of the diagonals
</span><span>
step 1
find CB
applying Pythagoras Theorem
AB</span>²=AC²+BC²------> BC²=AB²-AC²-----> BC²=5²-3²----> BC²=16
<span>BC=4
so
the diagonals are
(10+4) and (3+3)---------> 14 and 6
Area=(1/2)*[14*6]----> Area=42 units</span>²<span>
the answer Part 2) is
the area of a kite is 42 units</span>²
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